The quotient of 52 and the sum of

James and Terry open a savings account that has a 2.75% annual interest rate, compounded monthly. They deposited $500 into the a

zhuklara [117]

Answer:

$275

Step-by-step explanation:

This is what I got:

You first convert 2.75% into 0.0275

You then multiply 500 x 0.0275 = 13.75

Finally you multiply 13.75 x 20 = 275

so the answer should be 275

5 0

3 years ago

What is the smallest positive prime factor of 2017^2019 +2019^2017

kogti [31]

Answer:

17

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Juanita is making bread. She needs 3 1/2 cups of flour. Juanita only has 1/4 measuring cup. How many cups of flour will Juanita

jekas [21]

Answer:

if she uses a 1/4 measuring cup she would need to get 14 1/4 cups of flour

Step-by-step explanation:

7 0

3 years ago

A survey collected data on annual credit card charges in seven different categories of expenditures: transportation, groceries,

Andru [333]

Answer:

A. Null and alternative hypothesis:

$H_0: \mu_d=0\\\\H_a:\mu_d\neq 0$

B. Yes. At a significance level of 0.05, there is enough evidence to support the claim that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

P-value = 0.00002

C. As the difference is calculated as (population 1 − population 2), being population 1: groceries and population 2: dinning out, and knowing there is evidence that the true mean difference is positive, we can say that the groceries annual credit card charge is higher than dinning out annual credit card charge.

The point estimate is the sample mean difference d=$840.

The 95% confidence interval for the mean difference between the population means is (490, 1190).

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

Then, the null and alternative hypothesis are:

$H_0: \mu_d=0\\\\H_a:\mu_d\neq 0$

The significance level is 0.05.

The sample has a size n=42.

The sample mean is M=840.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=1123.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{1123}{\sqrt{42}}=173.2827$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{840-0}{173.2827}=\dfrac{840}{173.2827}=4.848$

The degrees of freedom for this sample size are:

$df=n-1=42-1=41$

This test is a two-tailed test, with 41 degrees of freedom and t=4.848, so the P-value for this test is calculated as (using a t-table):

$\text{P-value}=2\cdot P(t>4.848)=0.00002$

As the P-value (0.00002) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

At a significance level of 0.05, there is enough evidence to support the claim that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

We have to calculate a 95% confidence interval for the mean difference.

The t-value for a 95% confidence interval and 41 degrees of freedom is t=2.02.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_M=2.02 \cdot 173.283=350$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 840-350=490\\\\UL=M+t \cdot s_M = 840+350=1190$

The 95% confidence interval for the mean difference is (490, 1190).

7 0

3 years ago

in wereda election where four candidates appeared for election, the winning candidate received 36,000 votes which represented 45

Dmitry [639]

Let's see

Total votes be x

45% of x=3600
0.45x=3600
x=3600/0.45
x=8000

Now total percentage of vote

45+20+25+6=96%

Not voted=4%

Find not voted

0.04(8000)
320

Total voted

8000-320
7680

7 0

2 years ago

Read 2 more answers

The quotient of 52 and the sum of - 4 and -9