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2 years ago

1 1/3 x 5/8 Please help, no links or out of context answers, thank you!

Mathematics

2 answers:

natta225 [31]2 years ago

5 0

Answer:

so, i have a method of multiplying fractions, but im not going to strait give you the answer

Step-by-step explanation:

multiply the whole number (1) by the denominator (3) and then add it to the numerator (1).

you multiply the fractions from there.

this is a very fun way of doing fraction multiplying with mixed numbers!

have a good day! :D

s2008m [1.1K]2 years ago

5 0

I got 0.83333333333 or 5/24

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What is six more than twice a number x

natta225 [31]

Answer:

2x + 6

2 times the number x is 2x (2 times x)

six more than that would be +6

5 0

3 years ago

CAn you help me with ratios? Mrs. Sturkie mixed 3 quarts of blue paint and 2 quarts of red paint to make purple paint to her cla

fredd [130]

So as we already know the ratio is 3 quarts blue paint to 2 quarts red paint, also written as 3:2. if she only has 1 quart blue paint she will need half of a quart of red paint because the ratio has to remain the same amount. if you multiply one side then you must multiply the other. same goes with division. If she only has 1 quart of red paint then that shows she divided the 2 red by 2. There fore you would have to divided the 3 by 2 in order to get 1.5 which would then make the ratio 1.5:1

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3 years ago

I only need number 11 in the picture please help and show work

IgorLugansk [536]

Answer:

1 = 115°

2 = 115°

3 = 65°

Step-by-step explanation:

P=65, so S (3) =65

360-65-65=230

230/2=115

Q (1) = 115

R (2) = 115

3 0

3 years ago

Read 2 more answers

Assume that women's heights are normally distributed with a mean given by mu equals 62.5 in,and a standard deviation given by

Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with

$\mu$ = 62.5 in

$\sigma$ = 2.2 in

the normal probability density function is given by

$f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}$ , then

(a) $P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx$ = 0.5899

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking $P(\bar{X} < 63)$ where n = 37. $\bar{X}$ is normally distributed with mean 62.5 in and standard deviation $2.2/\sqrt{37}$ . So, the probability density function is given by