It would take the cheetah 6.25 seconds to run 2000 meters.
Answer:
<h2>693 m²</h2>
Step-by-step explanation:
This is a parallelogram.
The formula of an area of a parallelogram:
![A=bh](https://tex.z-dn.net/?f=A%3Dbh)
<em>b</em><em> - base</em>
<em>h</em><em> - height</em>
From the graph we have <em>b = 21m</em> and <em>h = 33m</em>.
Substitute:
![A=(21)(33)=693\ m^3](https://tex.z-dn.net/?f=A%3D%2821%29%2833%29%3D693%5C%20m%5E3)
9514 1404 393
Answer:
3.61 seconds
Step-by-step explanation:
The bird starts 50 feet in the air, so will come down to a height of 40 feet after 3.61 seconds.
We want to solve h = 40.
40 = -16t^2 +55t +50
16t^2 -55t -10 = 0
t = (55 +√(55^2 -4(16)(-10)))/(2(16)) = (55 + √3665)/32 ≈ 3.61060
The bird will be 40 ft above the ground the first time after about 3.61 seconds.
It is equivalent too 5.3 and 5.30
Answer:
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