F(x)= 2x²+4x-6 and g(x)=2x-2, find each function
1. (f/g) (x) = f(x)÷g(x) = (2x²+4x-6)÷(2x-2)
First factor both top and bottom:
(2x-2)(x+3)÷(2x-2) = x+3
2. f(a + 2) = plug (a+2) in anywhere there is an x in f(x)=2x²+4x-6 -->
2(a+2)^2 +4(a+2)-6 = 2(a^2+4a+4)+4a+8-6, now distribute:
2a^2+8a+8+4a+2, combine like terms
2a^2+12a+10
3. g(a/2) = plug (a/2) in anywhere there's an x in g(x)=2x-2:
2(a/2)-2 = a-2
Answer:
Step-by-step explanation:
If the center of the circle is at the origin, the general formula for the circle is
x^2 + y^2 = r^2.
Since r = 2 units in this particular problem, the equation of the circle is:
x^2 + y^2 = 2^2, or x^2 + y^2 = 4
Answer: linear
Step-by-step explanation:
Answer:
.0417
Step-by-step explanation:
.0 is 10th's place so if we had 50 percent it would be .5
.00 is ones place so 4 percent would be .04
.0000 is where fractions come in so 3 3/4 would be .00375
