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3 years ago

X + 2y = 4 y = -x - 1

Mathematics

1 answer:

anyanavicka [17]3 years ago

5 0

Answer:

(-6, 5)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Algebra I

Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

x + 2y = 4

y = -x - 1

Step 2: Solve for x

Substitution

Substitute in y: x + 2(-x - 1) = 4
Distribute 2: x - 2x - 2 = 4
Combine like terms: -x - 2 = 4
Isolate x term: -x = 6
Isolate x: x = -6

Step 3: Solve for y

Define equation: y = -x - 1
Substitute in x: y = -(-6) - 1
Multiply: y = 6 - 1
Subtract: y = 5

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To help with her retirement savings, Donna has decided to invest. Assuming an interest rate of 3.59% compounded quarterly, how m

cricket20 [7]

Answer:

We get the value of Principal amount i.e initial investment = $61640

Step-by-step explanation:

Interest rate r = 3.59% or 0.0359

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3 years ago

PLEASE HELP HELP ASAP ASAPP WILL GIVE 100 POINTS AND BRAINLEST! PLUS MY THANKS AND ADMIRATION PLEASE PLEASE!!

tatyana61 [14]

Answer:

First Picture ⇒ [B] a = -2, b = 1, and c = -5

Second Picture ⇒ First step: Identify a = 1, b = 3, c = -4

$x=\frac{-3\pm \sqrt{3^2-4\cdot \:1\cdot \left(-4\right)}}{2\cdot \:1}$

$x=\frac{-3\pm 5\sqrt{25}}{2}$

$x=\frac{-3\pm \:5}{2}$

$x=\frac{-3+5}{2},\:x=\frac{-3-5}{2\c}$

Third Picture ⇒ Missing Info

Fourth Picture ⇒ [A] $x=-\frac{5}{2},\:x=-3$

Fifth Picture ⇒ $x=\frac{5\pm\sqrt{1} }{2}$

Step-by-step explanation:

-------------------------------------------------------------------------------------------------------------

Identify the a,b, and c-values for this equation:

y = -2x² + x -5

Quadratic Formula:

ax²+bx+c=0

−2x²+1x−5=0

a = -2, b = 1, and c = -5

-------------------------------------------------------------------------------------------------------------

Order the steps for solving this equation using the quadratic formula.

x² + 3x - 4 = 0

Solving to see what are the steps:

First step: Identify a = 1, b = 3, c = -4

$x=\frac{-3\pm \sqrt{3^2-4\cdot \:1\cdot \left(-4\right)}}{2\cdot \:1}$

$x=\frac{-3\pm 5\sqrt{25}}{2}$

$x=\frac{-3\pm \:5}{2}$

$x_1=\frac{-3+5}{2\cdot \:1},\:x_2=\frac{-3-5}{2\cdot \:1}$

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Use the quadratic formula to find the solution set for 2x² + 15 = -11x.

Add 11x to both sides:

2x² + 15+11x = -11x+11x

Simplify

2x² + 11x+15 = 0

Now solve with quadratic formula..

$x_{1,\:2}=\frac{-11\pm \sqrt{11^2-4\cdot \:2\cdot \:15}}{2\cdot \:2}$

$x_{1,\:2}=\frac{-11\pm \:1}{2\cdot \:2}$

$x_1=\frac{-11+1}{2\cdot \:2},\:x_2=\frac{-11-1}{2\cdot \:2}$

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Hence, [A] $x=-\frac{5}{2},\:x=-3$

-------------------------------------------------------------------------------------------------------------

Suppose you are solving a quadratic equation and this is your work so far...

x ² - 5x + 6 = 0

Thus, we have:

$x=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:1\cdot \:6}}{2\cdot \:1}$

$x=\frac{-\left(-5\right)\pm \:1}{2\cdot \:1}$

$x=\frac{5\pm\sqrt{1} }{2}$

$x_1=\frac{-\left(-5\right)+1}{2\cdot \:1},\:x_2=\frac{-\left(-5\right)-1}{2\cdot \:1}$

$x=3,x=2$

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Kavinsky

6 0

2 years ago