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3 years ago

Which expression is equivalent to sin^2 x-sin x - 2/sin x -2

1 answer:

3 0

Set sin x to a variable, i.e. u

u^2-u-2/u-2.

Factor:

(u-2)(u+1)/(u-2)

Simplify by canceling the u-2s...

leaving u+1. Since we substituted u for sin x...
the answer is A. sin x + 1

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Drag each expression to show whether the product is less than 1, equal to 1, or greater than 1.

laila [671]

Answer:

967354176/8725762864 because it can be a common denomonater

Step-by-step explanation:

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2 years ago

If it is noon Pacific Time in the summer, what time is it in Boston?

Svetlanka [38]

D 3 it is a 3 hours difference

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3 years ago

Read 2 more answers

Which property is demonstrated in the equation 0 x 35 = 0?

Kisachek [45]

Answer:

Step-by-step explanation:

the property of zero,

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2 years ago

Point C is the Image of C (-4,-2) under a Reflection across the x-axis.

Svetradugi [14.3K]

Step-by-step explanation:

$\text {Reflection Rule for across the X-axis: } (x,y) \rightarrow (x,-y)$

Using the point C (-4,-2) and the refection rule:

$(-4,-2) \rightarrow(-4, 2)$

$\text {C' should be (-4,2)}$

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3 years ago

Consider the following hypothesis test.H0:μ1−μ2=0 Ha:μ1−μ2≠0The following results are for two independent samples taken from the

Julli [10]

Answer:

a) $z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

b) $p_v =2*P(z$

c) Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

Step-by-step explanation:

Information given

$\bar X_{1}= 104$ represent the mean for 1

$\bar X_{2}= 106$ represent the mean for 2

$\sigma_{1}= 8.4$ represent the population standard deviation for 1

$\sigma_{2}= 7.6$ represent the population standard deviation for 2

$n_{1}=80$ sample size for the group 1

$n_{2}=70$ sample size for the group 2

z would represent the statistic

Hypothesis to test

We want to check if the two means for this case are equal or not, the system of hypothesis would be:

H0: $\mu_{1}=\mu_{2}$

H1: $\mu_{1} \neq \mu_{2}$

The statistic would be given by:

$z =\frac{\bar X_1-\bar X_2}{\sqrt{\frac{\sigma^2_1^2}{n_1} +\frac{\sigma^2_2^2}{n_2}}}=$ (1)

Part a

Replacing we got:

$z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

Part b

The p value would be given by this probability:

$p_v =2*P(z$

Part c

Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

6 0

3 years ago