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Sati [7]
3 years ago
7

Which best describes the angles of some parallelograms?

Mathematics
1 answer:
Vinil7 [7]3 years ago
7 0
The answer is C. 4 obtuse angles could not make a 4 sided figure such as a parrallelogram. 4 acute angles is not possible for creating parallelograms either.
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Identify the expression that is equivalent to cot x/ csc x -1
Yuri [45]
Cotx = cosx/sinx
cscx = 1/sinx

If we plug these into your equation we get:
(cosx/sinx)/(1/sinx) - 1

Dividing by a number is the same as multiplying by its reciprocal so it can be rewritten as:
(cosx/sinx)(sinx) - 1 

The two sinx's cancel each other out so we end up with cosx - 1

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3 years ago
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liberstina [14]
15.

0.20*x = 0.01*x + 38 => 0.19*x = 38 =>( 19/100 )*x = 38 => x = 3800/19 => x = 200.
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Step-by-step explanation:

7 0
2 years ago
Find the first three iterates of the function f(z) = z2 + c with a value of c = 2 - 3i and an initial value of z0 = 1 + 2i.
Artist 52 [7]

Answer:

C

Step-by-step explanation:

We have: (I rewrote the function)

f(z_n)={z_{n-1}} ^2+c

Given that:

\displaystyle c=2-3i \text{ and } z_0 = 1 + 2 i

The first iterate will be:

\displaystyle \begin{aligned} f(z_1)&=(z_0)^2+c \\ &=(1+2i)^2+(2-3i) \\ &= (1+4i+4i^2)+(2-3i) \\ &=1+4i-4+2-3i \\ &=-1+i \end{aligned}

The second iterate will be:

\begin{aligned}f(z_2) &=(z_1)^2+c\\ &=(-1+i)^2+(2-3i) \\&= (1-2i+i^2)+(2-3i) \\&=1-2i-1+2-3i \\&=2-5i \end{aligned}

And the third iterate will be:

\begin{aligned} f(z_3)&=(z_2)^2+c\\ &=(2-5i)^2+(2-3i) \\ &=(4-20i+25i^2)+(2-3i) \\ &=4-20i-25+2-3i \\ &=-19-23i \end{aligned}

Hence, our answer is C.

3 0
3 years ago
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