3 years ago

How would you multiply. ? 3.5 2 ca D 52 3.5

Mathematics

1 answer:

hram777 [196]3 years ago

6 0

Answer:

1274Dac

Step-by-step explanation:

i used photomath but i think thats right hope this helps:)

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3 years ago

When simplifying 4x^3-10x^2+6x/2x^3+x^2-3x, what are the term(s) that can be cancelled

brilliants [131]

Answer:

x can be cancelled

Step-by-step explanation:

we are given

$\frac{4x^3-10x^2+6x}{2x^3+x^2-3x}$

Firstly, we will factor numerator and denominator

and then we can factor it

$4x^3-10x^2+6x=2x(2x^2-5x+3)$

$4x^3-10x^2+6x=2x(2x+1)(x-3)$

now, we can factor denominator

$2x^3+x^2-3x=x(2x^2+x-3)$

$2x^3+x^2-3x=x(x-1)(2x+3)$

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$\frac{4x^3-10x^2+6x}{2x^3+x^2-3x}=\frac{2x(2x+1)(x-3)}{x(x-1)(2x+3)}$

we can see that

both terms are having x common

so, x can be cancelled

So,

x can be cancelled

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4 years ago

How would you multiply. ? 3.5 2 ca D 52 3.5​

How would you multiply. ? 3.5 2 ca D 52 3.5