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Ivan
3 years ago
15

I’m so confused on how to find the answer to this

Mathematics
1 answer:
nalin [4]3 years ago
4 0

Step-by-step explanation:

download an app called algebrator its way easier than asking brainly

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Can someone explain these two math questions to me?<br><br> −2 + 4 ⋅ 32 − 6<br><br> 5 + 42 ÷ 2(3)
zepelin [54]
The first one would be 120 the second one would be 68
8 0
3 years ago
Read 2 more answers
When angles are complementary, the sum of their measures is 90 degrees.Two complementary angles have measures of 2x-10 degrees a
Mariana [72]

Complementary angles are those angles whose sum is 90 degree.

The measurement of two complementary angles are

(2x-10), (3x-10)

There sum have to be 90 degree. That is

2x-10+3x-10 = 90

Combining like terms ,

5x - 20 = 90

Moving 20 to right side

5x=110

Dividing both sides by 5

x =22

So the measurement of the angles are

2*22-10 , 3*22-10  \\&#10;34 degree,  56 degree

6 0
3 years ago
Find parametric equations for the line through the point (0, 2, 2) that is parallel to the plane x + y + z = 4 and perpendicular
Oxana [17]

Answer: X = 3t, Y =2 - t, Z =2

Step-by-step explanation: the plane

x + y + z =4has normal vector

M =<1,1,1> and the line

x = 1 + t, y = 2 − t, z = 2t has direction

v =<1, −1, 2>. So the vector

A= n × v

=<1, 1, 1> × <1, −1, 2>

=<2−(−1),1−2,−1−1>

=<3,−1,−2>

5 0
4 years ago
Which of these relations on {0, 1, 2, 3} are equivalence relations? Determine the properties of an equivalence re- lation that t
slava [35]

Answer:

The relations that are equivalence relations are a) and c)

Step-by-step explanation:

A relation on a set A is called an equivalence relation if it is reflexive, symmetric, and transitive

We are going to analyze each one.

a){ (0,0), (1,1), (2,2), (3,3) }

Is an equivalence relation because it has all the properties.

b){ (0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3) }

Is not an equivalence relation. Not reflexive: (1,1) is missing, not transitive: (0,2) and (2,3) are in the relation, but not (0,3)

c){ (0,0), (1,1), (1,2), (2,1), (2,2), (3,3) }

Is an equivalence relation because it has all the properties.

d){ (0,0), (1,1), (1,3), (2,2), (2,3), (3,1), (3,2) (3,3) }

Is not an equivalence relation. Not transitive: (1,3) and (3,2) are in the relation, but not (1,2)

e){ (0,0), (0,1) (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3) }

Is not an equivalence relation. Not symmetric: (1,2) is present, but not (2,1)Not transitive: (2,0) and (0,1) are in the relation, but not (2,1)

5 0
4 years ago
1, -5, 25, -125,... ​
nadezda [96]
The answer I believe is the third choice.
3, -2, -7, -12
These all fit into f(n)-5=f(n+1)
8 0
3 years ago
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