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Sergio039 [100]
3 years ago
11

Let's call a song danceable if it has a danceability of at least 0.7. What is the probability that an individual song has a danc

eability of at least 0.7
Mathematics
1 answer:
vfiekz [6]3 years ago
3 0

Answer:

32.54%

Step-by-step explanation:

To determine the probability that an individual song has a danceability of at least 0.7

Applying the excel formula below

=COUNTIF ( I2:I4771,">0.7") / ROWS( I2:I4771)

Hence ; The probability of an individual song having a danceability of at least 0.7 = 32,54%

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Y-x=15 y-x=5 using elimination
Galina-37 [17]

Answer:

No solution

Step-by-step explanation:

To eliminate is to get rid of one of the variables.

You can choose to either add each term in the equations or subtract each term in the equation.

For a variable to be eliminated, there must one pair that have the same constant with it. Each equation already has the same constant with a variable.

Try adding them.

.     y - x = 15

<u>+    y - x = 5</u>

2y - 2x = 20   No variables were eliminated.

Try subtracting.

.     y - x = 15

<u>-     y - x = 5</u>

0y - 0x  = 10   All variables were eliminated.

.         0 = 10     This is false.

This system of equations cannot be solved.

Graphically, these two lines would have the same slope and are parallel. The solution to a system is same as the point of intersection. Parallel lines never meet, never intersect, therefore there is no solution.

3 0
3 years ago
Which statement describes the inverse of m(x) = x^2 – 17x?
DochEvi [55]

Given:

The function is

m(x)=x^2-17x

To find:

The inverse of the given function.

Solution:

We have,

m(x)=x^2-17x

Substitute m(x)=y.

y=x^2-17x

Interchange x and y.

x=y^2-17y

Add square of half of coefficient of y , i.e., \left(\dfrac{-17}{2}\right)^2 on both sides,

x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2

x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2

x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2        [\because (a-b)^2=a^2-2ab+b^2]

Taking square root on both sides.

\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}

Add \dfrac{17}{2} on both sides.

\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y

Substitute y=m^{-1}(x).

m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}

We know that, negative term inside the root is not real number. So,

x+\left(\dfrac{17}{2}\right)^2\geq 0

x\geq -\left(\dfrac{17}{2}\right)^2

Therefore, the restricted domain is x\geq -\left(\dfrac{17}{2}\right)^2 and the inverse function is m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}.

Hence, option D is correct.

Note: In all the options square of \dfrac{17}{2} is missing in restricted domain.

7 0
3 years ago
89b - 34 = 411<br> help me new answer
Bess [88]

Answer:

b = 5

Step-by-step explanation:

89b = 411 + 34 (445)

89b = 445

b = 5

3 0
3 years ago
Read 2 more answers
**The following scenario is for #12, #13, and #14 on this test.** A school chorus has 90 sixth grade students and 75 seventh gra
givi [52]

Answer:

The music director can make 15 groups of performers with 6 sixth grade students and 5 seventh grade students in each group.

Step-by-step explanation:

A school chorus has 90 sixth-grade students and 75 seventh-grade students.

Factor these two numbers:

Find GCF(90,75):

Now,

Therefore, the music director can make 15 groups of performers with 6 sixth grade students and 5 seventh grade students in each group.

6 0
2 years ago
the length of a rectangular sign is 5 times its width. If the sign's perimeter is 24inches, what is the signs area
anastassius [24]

Answer:

20 square inches

Step-by-step explanation:

Set width of sign to x.

Set length of sign to y.

5x=y

2(x+y)=24 inches

2(x+5x)=24 inches

12x=24 inches

width = 2 inches

length = 10 inches

Area = 20 square inches

PLEASE GIVE BRAINLIEST

6 0
3 years ago
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