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Nezavi [6.7K]
3 years ago
7

The box plots show male and female grades in a physics class. Which of the following best describes the information about the in

terquartile ranges? (SEE ATTACHED).

Mathematics
2 answers:
AlekseyPX3 years ago
8 0

Answer:

I think the other one is right

Step-by-step explanation:

Nastasia [14]3 years ago
4 0
My dude I don’t know I’m just here
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Find the EXACT value of sin(A−B) if cos A = 3/5 where A is in Quadrant IV and cos B = 12/13 where B is in Quadrant IV. Assume al
MissTica

\bf \textit{Sum and Difference Identities} \\\\ sin(\alpha - \beta)=sin(\alpha)cos(\beta)- cos(\alpha)sin(\beta)

well, for both angles A and B we're on the IV Quadrant, meaning, the sine is negative, the cosine is positive, likewise, the opposite side is negative and the adjacent side for the angle is positive.

\bf cos(A)=\cfrac{\stackrel{adjacent}{3}}{\underset{hypotenuse}{5}}\qquad \qquad \stackrel{\textit{getting the opposite side}}{b=\pm\sqrt{5^2-3^2}}\implies b = \pm 4 \\\\\\ \stackrel{IV~Quadrant}{b = -4}\qquad \qquad sin(A)=\cfrac{\stackrel{opposite}{-4}}{\underset{hypotenuse}{5}} \\\\[-0.35em] ~\dotfill\\\\ cos(B)=\cfrac{\stackrel{adjacent}{12}}{\underset{hypotenuse}{13}}\qquad \qquad \stackrel{\textit{getting the opposite side}}{b=\pm\sqrt{13^2-12^2}}\implies b = \pm 5

\bf \stackrel{IV~Quadrant}{b = -5}\qquad \qquad sin(B)=\cfrac{\stackrel{opposite}{-5}}{\underset{hypotenuse}{13}} \\\\[-0.35em] ~\dotfill\\\\ sin(A-B)=\cfrac{-4}{5}\cdot \cfrac{12}{13}-\left( \cfrac{3}{5}\cdot \cfrac{-5}{13} \right)\implies sin(A-B)=\cfrac{-48}{65} - \left( \cfrac{-15}{65} \right) \\\\\\ sin(A-B)=\cfrac{-48}{65} + \cfrac{15}{65}\implies sin(A-B)=\cfrac{-33}{65}

4 0
3 years ago
Help. It’s due today plz I’m begging u :/ click the picture to make up bigger
Pani-rosa [81]

Answer:

im pretty sure B 7.5 units

Step-by-step explanation:

6 0
3 years ago
The rate of change of the function f(x) = 8 sec(x) + 8 cos(x) is given by the expression 8 sec(x) tan(x) − 8 sin(x). Show that t
liq [111]

Answer:

Shown - See explanation

Step-by-step explanation:

Solution:-

- The given form for rate of change is:

                              8 sec(x) tan(x) − 8 sin(x).

- The form we need to show:

                              8 sin(x) tan2(x)

- We will first use reciprocal identities:

                              8\frac{sin(x)}{cos^2(x)} - 8sin(x)

- Now take LCM:

                            8\frac{sin(x)- sin(x)*cos^2(x)}{cos^2(x)}

- Using pythagorean identity , sin^2(x) + cos^2(x) = 1:

                            8*sin(x)*\frac{1- cos^2(x)}{cos^2(x)} = 8*sin(x)*\frac{sin^2(x)}{cos^2(x)}

- Again use pythagorean identity tan(x) = sin(x) / cos(x):

                            8*sin(x)*tan^2(x)

8 0
4 years ago
Read 2 more answers
Estimate the unit rate of 12 pairs of socks sell for $5.79 any body knows what the answer is?​
Minchanka [31]

Answer:

About  $0.24 per sock

Step-by-step explanation:

12 pairs = 24 socks

5.79/24 = 0.24125

8 0
3 years ago
Read 2 more answers
In taking a multiple-choice test, there are four possible answers for each problem, only one of which is correct. Assume that so
Degger [83]
Total number of events
4^25

Probabilty to get all 25 randomly,

1^(4^25)
7 0
3 years ago
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