| u | = √(2² + (-1²)) = √5
| v | = √ ( 1² + (-8)² = √65
cos (u,v) = ( u * v ) / (| u | * | v |) =
(2 * 1 + ( -1 ) * ( - 8 )) / √5 √ 65 = (2 + 8) / √5 √65 = 10 / (√5 √ 65 )
The length of a larger diagonal:
d 1² = | u |² + 2 |u| |v| + | v |² = 5 + (2 √5 √65 * 10 / √5 √65 )+65
d 1² = 70 + 20 = 90
d 1 = √ 90 = 3√10
d 2² = 70 - 20 = 50
d 2 = √50 = 5√2
Answer:
The lengths of the diagonals are: 3√10 and 5√2 .
The dimensions should be 1 2/3 feet by 1 1/2 feet.
To find these amounts, we simply multiply the length of the snake by the given fraction.
For the length, multiply by 2/3.
For the width, multiply by 1/2.
68-40=28
28/4=7
therefore, 7 is your answer
(Hope it helps my friend ^_^)
Point, line, plane, Ray, segment, circle for a few
Answer:
a total of 24 presents can be wrapped
Step-by-step explanation:
6 x 3 = 18 feet of ribbon
18 x 12 = 216 inches of ribbon
216/9 = 24 presents can be wrapped
