Answer:
no because on is equal to 3 when plugged in and the other is equal to 4 when plugged in.
Step-by-step explanation:
Answer:
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where the heart is go left one and a half point
Answer: 122.5
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Explanation:
First thing to do is to find the perimeter of figure B. Add up all the sides and we get: 5+9+9+12 = 14+21 = 35.
The scale factor 7:2 means that if the perimeter of figure A was 7, then the perimeter of figure B would be 2. Or it could be 14 for A and 4 for B. And so on. The idea is that the two perimeters scale up or down together. This allows us to set up the proportion below in which we can solve for x
(perimeter of A)/(perimeter of B) = 7/2
x/35 = 7/2
x*2 = 35*7 .... cross multiply
2x = 245
2x/2 = 245/2 .... divide both sides by 2
x = 122.5
The perimeter of figure A is 122.5
Answer:
Step-by-step explanation:
The antiderivative of the function is the same as the integral. To find the integral or antiderivative, reverse the process of differentiation method. Currently the function has degree 1. Through integration we increase the degree of each term by 1 and divide by the degree.
Thus 35 - 9x becomes . We add a constant C for any possible constant that was eliminated during differentiation.
The general formula for the total surface area of a regular pyramid is T. S. A. =12pl+B where p represents the perimeter of the base, l the slant height and B the area of the base
To find the surface area of a regular triangular pyramid, we use the formula SA = A + (3/2)bh, where A = the area of the pyramid's base, b = the base of one of the faces, and h = height of one of the faces.
We can also label the length (l), width (w), and height (h) of the prism and use the formula, SA=2lw+2lh+2hw, to find the surface area.
To find surface area for a rectangular prism, use the formula SA = 2ab + 2bc + 2ac, where a is the width, b is the height, and c is the length. If you're trying to find the surface area of a triangular prism, use the formula SA = 2a + ph, where a is the area of the triangle, p is the perimeter, and h is the height
Hope that was helpful.Thank you!!!
