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Anton [14]
3 years ago
5

PLEASE HELP WITH THE QUESTION IN THE PICTURE!!!

Mathematics
1 answer:
Likurg_2 [28]3 years ago
6 0
Omg another one....9 :)
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Can someone please help me with this!!!!!<br><br> 2/5 ÷ 8 1/2 = ?
pav-90 [236]
The answer would be 4/85


1. 2/5 ÷ 8 * 2 + 1  over 2

2. 2/5 ÷ 16 + 1 over 2

3. 2/5 ÷ 17/2

4. 2/5 * 2/17

5. 2 * 2 over 5 * 17

6. 4 over 5 * 17

7. finally 4/85
7 0
3 years ago
Read 2 more answers
the smallest angle in a triangle is one-third of the largest angle. the third angle is 10degrees more than the smallest angle. f
Alex787 [66]
A: smallest 
c: largest
b: third 
a+b+c=180
a=c/3
b=10+a
solve it
a=34
b=44
c=102
5 0
3 years ago
the perimeter of the floor of a room is 18 metre and its height is 3 cm what is the area of 4 walls of the room​
Lina20 [59]

Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.

Given:

Perimeter of the floor of a room = 18 metre

Height of the room = 3 metre

To find:

The area of 4 walls of the room.

Solution:

We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.

The curved surface area of the cuboid is

C.S.A.=2h(l+b)

Where, h is height, l is length and b is breadth.

Perimeter of the rectangular base is 2(l+b). So,

C.S.A.=\text{Perimeter of the base} \times h

Putting the given values, we get

C.S.A.=18\times 3

C.S.A.=54

Therefore, the area of 4 walls of the room is 54 sq. metres.

7 0
3 years ago
the table shows the highest of four students arrange the students in order from shortest to tallest Kim 56.03 + x + 56.3 + 56.14
saul85 [17]
56.03 56.14 56.3 57.1
6 0
3 years ago
The dot plots below show the scores for a group of students for two rounds of a quiz: Two dot plots are shown one below the othe
miskamm [114]

Answer:

The inference that can be made using the dot plot is:

    The range of round 1 is greater than the round 2 range.

Step-by-step explanation:

<u>Round 1:</u>

Score                Frequency

  1                          0

  2                          2

  3                          3

  4                          2  

  5                          1

Hence, the minimum score of Round 1 is: 2

maximum score is: 5

Hence, Range=Maximum value-Minimum score

                      =5-2

                       =3

Similarly, <u>Round-2</u>

Score                Frequency

  1                          0

  2                         0

  3                          0

  4                          4  

  5                          4

Hence, the minimum score of Round 1 is: 4

maximum score is: 5

Hence, Range=Maximum value-Minimum score

                      =5-4

                       =1

The scores of round 2 are higher than round-1.

Since round 2 have a higher frequency for higher scores as compared to round-1.

Hence, Range of round 1 is greater than the range of Round-2.

 

6 0
3 years ago
Read 2 more answers
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