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Trava [24]
3 years ago
11

If John loses -$50 over 10 days, on average how much does he lose in one day?

Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
6 0

Answer:

$5

Step-by-step explanation:

take the total ($50) and divide that by the amount of days you lose said money (10)

bonus: cat

tankabanditka [31]3 years ago
4 0

Answer:

$5

Step-by-step explanation:

If John loses $50 over 10 days, just divide 50 by ten.

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4 0
3 years ago
A. Use the​ one-mean t-interval procedure with the sample​ mean, sample​ size, sample standard​ deviation, and confidence level
PtichkaEL [24]

Answer:

a) (17.227, 22.773)

b) 2.773

c) 2.773

Step-by-step explanation:

Given:

Sample size, n = 25

Standard deviation, s = 4

Sample mean, x' = 20

Level of significance, a = 0.98 = 1 - 0.98 = 0.02

The degrees of freedom, df, for a t-distribution = n - 1 = 25 - 1 = 24

Using the t table, the Critical value = t_\alpha _/_2, _d_f = t_0_._0_2_/_2, _2_4 = t_0_._0_1_, _2_4 = 3.4668

Margin of error, E = t_\alpha _/_2, _d_f * \frac{\sigma}{\sqrt{n}} = 3.4668 * \frac{4}{\sqrt{25}} = 2.773

Limits of 98% confidence interval, we have:

Lower limit : x' - M.E = 20 - 2.773 = 17.227

Upper limit: x' + M.E = 20 + 2.773 = 22.773

Therefore, (17.227, 22.773) is 98% confidence interval.

b) Let's the margin of error by taking half the length of the confidence interval.

Since we are to use half the length of CI, we have:

M.E = \frac{22.773 - 17.227}{2} = 2.773

c)M.E = t_\alpha _/_2, _d_f *s/\sqrt{n}

= t * \frac{s}{\sqrt{n}} = 3.4668 * \frac{4}{\sqrt{25}} = 2.773

4 0
3 years ago
Please help! Photo inside!
I am Lyosha [343]

Hello from MrBillDoesMath!

Answer:

Area of tile = 24

Discussion:

The area of the triangle is


(1/2) Base * height =

(1/2) 6 * 8 =

(1/2) 48 =

24

Thank you,

MrB

4 0
3 years ago
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iogann1982 [59]
Y = 1/4 x - 2


=> a linear function => a straigh line


=> slope = the coefficient of x => slope = 1/4


=> x = 0 => the y-intercept = -2


=> y = 0 => 0 = 1/4 x - 2 =>x = 8 => point (8,0)


With all that information you can identify the graph because it is a straight line that passes through (0,-2) and (8,0), its inclination (slope) is 1/4, and the graph goes through the quadrants I, III and IV (there are no points in the quadrant II)..  
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Airida [17]

Answer:

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Step-by-step explanation:

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