All categories

3 years ago

What are the solution(s) of x^2 - 4 = 10?

Mathematics

1 answer:

dedylja [7]3 years ago

4 0

$x^2-4=10\ \ \ |+4\\\\x^2=14\to x=\pm\sqrt{14}$

You might be interested in

A line passes through the point A(n,4) and B(8,6) and is parallel to y=2x-5. what is the value of n

NARA [144]

The slope-intercept form:

y = mx + b

m - slope

b - y-intercept

We have the line y = 2x - 5.

The parallel lines have the same slope. Therefore we have y = 2x + b.

Put the coordinates of the point B(8, 6) to the equation:

6 = 2(8) + b

6 = 16 + b subtract 16 from both sides

-10 = b → b = -10

The equation of a line: y = 2x - 10.

Put the coordinates of the point A(n, 4) to the equation:

4 = 2(n) - 10 add 10 to both sides

14 = 2n divide both sides by 2

8 0

3 years ago

PLEASE HELLPOP ITS EASY

Soloha48 [4]

Scale factor is 4
20/5=4
5*4=20

4 0

3 years ago

a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample s

Alex

Answer:

95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

Step-by-step explanation:

We are given that a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample standard deviation of the number of tissues per box is 97.

Firstly, the pivotal quantity for 95% confidence interval for the population variance is given by;

P.Q. = $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2}__n_-_1$

where, $s^{2}$ = sample variance = $97^{2}$ = 9409

n = sample of boxes = 15

$\sigma^{2}$ = population variance

Here for constructing 95% confidence interval we have used chi-square test statistics.

So, 95% confidence interval for the population variance, $\sigma^{2}$ is ;

P(5.629 < $\chi^{2}__1_4$ < 26.12) = 0.95 {As the critical value of chi-square at 14

degree of freedom are 5.629 & 26.12}

P(5.629 < $\frac{(n-1)s^{2} }{\sigma^{2} }$ < 26.12) = 0.95

P( $\frac{5.629 }{(n-1)s^{2} }$ < $\frac{1}{\sigma^{2} }$ < $\frac{26.12 }{(n-1)s^{2} }$ ) = 0.95

P( $\frac{(n-1)s^{2} }{26.12 }$ < $\sigma^{2}$ < $\frac{(n-1)s^{2} }{5.629 }$ ) = 0.95

95% confidence interval for $\sigma^{2}$ = [ $\frac{(n-1)s^{2} }{26.12 }$ , $\frac{(n-1)s^{2} }{5.629 }$ ]

= [ $\frac{14 \times 9409 }{26.12 }$ , $\frac{14 \times 9409 }{5.629 }$ ]

= [5043.11 , 23401.31]

Therefore, 95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

6 0

3 years ago

Solve the equation for x (if possible please show work)

Daniel [21]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{x = - 4}}}}}$

Step-by-step explanation:

$\sf{3x - 5 = 2x - 9}$

Move 2x to left hand side and change it's sign

⇒ $\sf{3x - 2x - 5 = - 9}$

Move 5 to right hand side and change it's sign

⇒ $\sf{3x - 2x = - 9 + 5}$

Collect like terms

⇒ $\sf{x = - 9 + 5}$

Calculate

⇒ $\sf{x = - 4}$

Hope I helped!

Best regards!!

6 0

4 years ago

If The diameter of a circle is 14 yards.what is the circles circumference

amm1812

Answer:

14π yards^2, or 43.98^2 yards rounded to 2dp

Step-by-step explanation:

circumference = diameter x π

6 0

3 years ago