Answer:

Step-by-step explanation:
Starting from the y-intercept of
you do
by either moving four blocks <em>south</em><em> </em>over one block <em>west</em><em> </em>or four blocks <em>north</em><em> </em>over one block<em> east</em><em> </em>[<em>west</em> and <em>south</em> are negatives]. Next, we have to determine the types of inequality symbols that are suitable for this graph, which will be <em>less</em><em> </em><em>than</em><em> </em>and <em>greater</em><em> </em><em>than</em><em> </em>since this is a <em>dashed</em><em> </em><em>line</em><em> </em>graph. We then use the zero-interval test [test point (0, 0)] to ensure whether we shade the opposite portion [portion that does not contain the origin] or the portion that DOES contain the origin. At this step, we must verify the inequalities as false or true:
<em>Greater</em><em> </em><em>than</em>
☑
<em>Less</em><em> </em><em>than</em><em> </em>
![\displaystyle 0 < 4[0] - 2 → 0 ≮ -2](https://tex.z-dn.net/?f=%5Cdisplaystyle%200%20%3C%204%5B0%5D%20-%202%20%E2%86%92%200%20%E2%89%AE%20-2)
This graph is shaded in the portion of the origin, so you would choose the <em>greater</em><em> </em><em>than</em><em> </em>inequality symbol to get this inequality:

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Length of the base = 8
Length of the hypotenuse = 17

The length of the third side ''
".


Using Pythagoras theorem, we have
(Perpendicular)² + (Base)² = (Hypotenuse)²
+ (8)² = (17)²
+ 64 = 289
= 289 - 64
= 225
= 
= 
Therefore, the length of the missing side
is
.

(15)² + (8)² = (17)²
225 + 64 = 289
289 = 289
L.H.S. = R. H. S.
Hence verified.

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2(5x)2(-7)=2x+10
2(5x)= 10x
2(-7)=-14
10x-14=2x+10
Solve:
10x-2x=8x
8x-14=10
14+10=24
8x=24
24/8=3
X=3