Ask question

Ask question

All categories

3 years ago

10

How do I find QS here?

1 answer:

juin [17]3 years ago

4 0

Answer: 12.
To solve this problem, let's first solve for x. Thi is easiest done by figuring what QR is in terms of x using two equations, both from different lines.
In the first line: QR = 15 - 4x.
In the third line:QR = 13x - 1 - x = 12x - 1.
Now, we have to set these equations equal to each other. 15 - 4x = 12x - 115 = 16x - 116x = 16x = 1
Next, we take line three, 13x - 1, and substitute x as 1. The answer is 12.

You might be interested in

208 divi by 6.4 What is the quotient for the equation above?

andrey2020 [161]

Answer:

B

Step-by-step explanation:

208 divided by 6.4 = 32.5

8 0

2 years ago

Read 2 more answers

Grasshoppers are distributed at random in a large field according to a Poisson process with parameter a 5 2 per square yard. How

HACTEHA [7]

In this question, the Poisson distribution is used.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Parameter of 5.2 per square yard:

This means that $\mu = 5.2r$ , in which r is the radius.

How large should the radius R of a circular sampling region be taken so that the probability of finding at least one in the region equals 0.99?

We want:

$P(X \geq 1) = 1 - P(X = 0) = 0.99$

Thus:

$P(X = 0) = 1 - 0.99 = 0.01$

We have that:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.2r}*(5.2r)^{0}}{(0)!} = e^{-5.2r}$

Then

$e^{-5.2r} = 0.01$

$\ln{e^{-5.2r}} = \ln{0.01}$

$-5.2r = \ln{0.01}$

$r = -\frac{\ln{0.01}}{5.2}$

$r = 0.89$

Thus, the radius should be of at least 0.89.

Another example of a Poisson distribution is found at brainly.com/question/24098004

3 0

3 years ago

At the beginning of an experiment, the temperature of a solution was 48°C. During a 6-hour

ExtremeBDS [4]

9514 1404 393

Answer:

-2.2(6) +1.8(4) . . . temperature change
42 °C

Step-by-step explanation:

At the end of the first 6 hours, the temperature change was ...

(-2.2 K/h)(6 h) = -13.2 K

The change in the next 4 hours was ...

(1.8 K/h)(4 h) = 7.2 K

Then the total change over the 10-hour period was ...

(-2.2)(6) +(1.8)(4) . . . . . expression for temperature change

This evaluates to -13.2 +7.2 = -6.

__

The final temperature is the sum of the initial temperature and the temperature change:

final temperature = 48 °C -6 °C = 42 °C

_____

<em>Additional comment</em>

When temperature is measured on the Celsius scale, a change of 1 degree is called a kelvin (K).

8 0

3 years ago

What is 3.38 rounded to the nearest tenth of a dollar

lina2011 [118]

It would round to $3.40

4 0

3 years ago

If I drop a book from the same height as a feather which will land first?

g100num [7]

The book will land first

4 0

3 years ago

Read 2 more answers