All categories

3 years ago

How do I find QS here?

Mathematics

1 answer:

juin [17]3 years ago

4 0

Answer: 12.
To solve this problem, let's first solve for x. Thi is easiest done by figuring what QR is in terms of x using two equations, both from different lines.
In the first line: QR = 15 - 4x.
In the third line:QR = 13x - 1 - x = 12x - 1.
Now, we have to set these equations equal to each other. 15 - 4x = 12x - 115 = 16x - 116x = 16x = 1
Next, we take line three, 13x - 1, and substitute x as 1. The answer is 12.

You might be interested in

Scores on the Critical Reading portion of the SAT college entrance test in a recent year were roughly Normal with mean 496 and s

Sliva [168]

Answer:

C. 115 / square of 100 = 11.5

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\sigma = 115, n = 100$ . So

$s = \frac{115}{\sqrt{100}} = 11.5$

So the correct answer is:

C. 115 / square of 100 = 11.5

5 0

3 years ago

Which statement best compared the graphs

AleksandrR [38]

Answer is D it moves 8 to the right and up 4

3 0

3 years ago

Directed line segment PT has endpoints whose

crimeas [40]

Answer:

(2 , 5)

Step-by-step explanation:

point (x,y) that divides the segment PI in the ratio 2 to 1

PD=4 - (-2) = 6 PE/ED=2/1 PE=2ED PE+ED=6 3ED=6 ED=2 PE=4

coordinate of E (2,1) .... 2 is x coordinate of E

DI=7-1=6 DF/FI=2/1 DF=4

coordinate of F (4,5) .... .... 5 is y coordinate of E

CF // PD PC/CI=DF/FI=2/1

C (2,5)

4 0

3 years ago

a store buys a jacket for 20.00 then sells it 80% more than that. wwhat is the selling price of the jacket now? please help

ikadub [295]

It would be $36.00! Hope this helps!

6 0

4 years ago

Find the diameter of a sphere with a surface area of 196π square centimeters

aleksandr82 [10.1K]

$\textit{surface area of a sphere}\\\\ SA=4\pi r^2 ~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ SA=196\pi \end{cases}\implies \begin{array}{llll} 196\pi =4\pi r^2\implies \cfrac{196\pi }{4\pi }=r^2 \implies 49=r^2 \\\\\\ \sqrt{49}=r\implies 7=r~\hfill \underset{diameter}{\stackrel{2(7)}{14}} \end{array}$

7 0

2 years ago