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Marrrta [24]
2 years ago
9

M&M plain candies have a normally distributed weight with a mean of 0.8565 g and a standard

Mathematics
1 answer:
Alex_Xolod [135]2 years ago
3 0

Answer:

0.89417

Step-by-step explanation:

Using the relation to obtain the Zscore :

Z = (x - mean) ÷ standard deviation / sqrt(n)

x = 0.8535

Mean = 0.8565

Standard deviation = 0.0518

Sample size, n = 465

P(x ≤ 0.8535) = (0.8535 - 0.8565) ÷ 0.0518/sqrt(465)

P(x ≥ 0.8535) = - 0.003 / 0.0024021

P(x ≥ 0.8535) = - 1.249

P(Z ≥ - 1.249) = 0.89417

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\bf \stackrel{mixed}{2\frac{1}{3}}\implies \cfrac{2\cdot 3+1}{3}\implies \stackrel{improper}{\cfrac{7}{3}}
~\hfill
\stackrel{mixed}{4\frac{2}{3}}\implies \cfrac{4\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{14}{3}}


\bf \stackrel{mixed}{1\frac{1}{2}}\implies \cfrac{1\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{3}{2}}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
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