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Marrrta [24]
2 years ago
9

M&M plain candies have a normally distributed weight with a mean of 0.8565 g and a standard

Mathematics
1 answer:
Alex_Xolod [135]2 years ago
3 0

Answer:

0.89417

Step-by-step explanation:

Using the relation to obtain the Zscore :

Z = (x - mean) ÷ standard deviation / sqrt(n)

x = 0.8535

Mean = 0.8565

Standard deviation = 0.0518

Sample size, n = 465

P(x ≤ 0.8535) = (0.8535 - 0.8565) ÷ 0.0518/sqrt(465)

P(x ≥ 0.8535) = - 0.003 / 0.0024021

P(x ≥ 0.8535) = - 1.249

P(Z ≥ - 1.249) = 0.89417

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Graph.<br><br> F(x) = |2x-6| + 3
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3 years ago
An electronics hobbyist has three electronic parts cabinets with two drawers each.
Andrews [41]

Answer:

a) 0.5 = 50% probability that an NPN transistor will be selected.

b) 0.3333 = 33.33% probability that it came from the cabinet that contains both types

c) 66.67% probability that it comes from the cabinet that contains only NPN transistors

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

a) What is the probability that an NPN transistor will be selected?

1/3 probability that the first cabinet is chosen. This cabinet has two transistors, both of which are NPN, so 100% probability of selecting a NPN transistor.

1/3 probability that the second cabinet is chosen. This cabinet has two transistors, both of which are PNP, so 0% probability of selecting a NPN transistor.

1/3 probability that the second cabinet is chosen. This cabinet has two transistors, one of which is NPN, so 50% probability of selecting a NPN transistor.

So

p = \frac{1}{3}*1 + \frac{1}{3}*0 + \frac{1}{3}*0.5 = \frac{1}{3} + \frac{1}{6} = \frac{2}{6} + \frac{1}{6} = \frac{3}{6} = 0.5

0.5 = 50% probability that an NPN transistor will be selected.

b) Given that the hobbyist selects an NPN transistor, what is the probability that it came from the cabinet that contains both types?

Here we use the conditional probability formula.

Event A: NPN transistor

Event B: From the third cabinet.

50% probability that an NPN transistor will be selected, so P(A) = 0.5.

1/6 probability that it is from the third cabinet and NPN, so P(A \cap B) = \frac{1}{6}

The desired probability is:

P(B|A) = \frac{\frac{1}{6}}{0.5} = 0.3333

0.3333 = 33.33% probability that it came from the cabinet that contains both types.

c) Given that an NPN transistor is selected what is the probability that it comes from the cabinet that contains only NPN transistors?

Either it comes from the cabinet with only NPN transistors, or it comes from the cabinet with both types of transistors. The sum of the probabilities of these outcomes is 100%. So

x + 33.33 = 100

x = 66.67

66.67% probability that it comes from the cabinet that contains only NPN transistors

6 0
3 years ago
Matter is in a liquid state when its temperature is between its melting point and its boiling point. Suppose that some substance
slavikrds [6]

Answer:

x<39.76 OR x>388.23 (In degrees Celsius.

Step-by-step explanation:

Melting point is when a a substance turns from a solid to liquid, and boiling point is the point where it turns from a liquid to a gas. That means in between these points is when the matter is in the liquid state, so it could be anything not included from the range 39.76-388.23.

7 0
2 years ago
A plumber pays $3.60 for 60 centimeters of pipe.Explain how the plumber can use unit cost of the pipe to find the cost of buying
kvv77 [185]
3.60 / 60cm = .06/cm or 6 cents per centimeter
100cm = 1m
$.06 * 100cm = $6.00 / m
100m = 100 * $6.00
= $600
5 0
3 years ago
Read 2 more answers
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