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Marrrta [24]
3 years ago
9

M&M plain candies have a normally distributed weight with a mean of 0.8565 g and a standard

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
3 0

Answer:

0.89417

Step-by-step explanation:

Using the relation to obtain the Zscore :

Z = (x - mean) ÷ standard deviation / sqrt(n)

x = 0.8535

Mean = 0.8565

Standard deviation = 0.0518

Sample size, n = 465

P(x ≤ 0.8535) = (0.8535 - 0.8565) ÷ 0.0518/sqrt(465)

P(x ≥ 0.8535) = - 0.003 / 0.0024021

P(x ≥ 0.8535) = - 1.249

P(Z ≥ - 1.249) = 0.89417

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harina [27]
A)
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4/100 x + 400≥460

b)
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3 years ago
The numbers 5, 6, 7, and 8 are randomly arranged to create a four-digit number. What is the probability that the number formed i
myrzilka [38]

Using the <u>arrangements and the probability concept</u>, it is found that there is a 0.75 = 75% probability that the number formed is not divisible by 4.

  • A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.
  • The number of possible arrangements of n elements is given by A_n = n!

In this problem, there are 4 elements, hence n = 4, T = A_4 = 4! = 24.

A number is a multiple of 4 if the <u>number composed by it's last 2 digits are multiples of 4</u>.

  • Hence, the possible options for the last 2 digits are: 56, 68, 76.
  • For each of them, there are A_2 = 2! = 2 options for the first 2 digits, hence, there will be 2 x 3 = 6 multiples of 4.

The other 18 numbers formed are not divisible by 4, hence:

p = \frac{18}{24} = 0.75

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For more on <u>arrangements and probabilities</u>, you can check brainly.com/question/24437717

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2 years ago
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