Answer:
(115.2642, 222.7358).
Step-by-step explanation:
Given data:
type A: n_1=60, xbar_1=1827, s_1=168
type B: n_2=180, xbar_2=1658, s_2=225
n_1 = sample size 1, n_2= sample size 2
xbar_1, xbar_2 are mean life of sample 1 and 2 respectively. Similarly, s_1 and s_2 are standard deviation of 1,2.
a=0.05, |Z(0.025)|=1.96 (from the standard normal table)
So 95% CI is
(xbar_1 -xbar_2) ± Z×√[s1^2/n1 + s2^2/n2]
=(1827-1658) ± 1.96×sqrt(168^2/60 + 225^2/180)
= (115.2642, 222.7358).
sqrt(575) = 23.979
so 23 is one number
575/23 = 25
the two numbers would be 23 * 25
25 is the largest one
Let x be ml of 5% soln.
let 500-x be ml of 25% soln.
.
x*.05=.05x
(500-x)*.25=125-.25x
500*.20=100
.
.05x+125-.25x=100
-.2x=-25
x=-25/-.2
x=125 ml of 5% soln.
500-x=375 ml of 25% soln.
.
Check:
125*.05= 6.25
375*.25=93.75
---------------
========100
Answer:
The 95% confidence interval is 
Step-by-step explanation:
From the question we are told that
The sample size is n = 26
The mean is 
The standard deviation is 
From the question we are told the confidence level is 95% , hence the level of significance is
=> 
Generally from the normal distribution table the critical value of 
is
Generally the margin of error is mathematically represented as
=> 
=> 
Generally 95% confidence interval is mathematically represented as
=> 
=>
the boiling point of jet fuel is 329 degrees F. Rounded to the nearest degree, what is the temperature in degrees Celcius? Use the Formula: C = 5/9(F - 32), where C represents degrees celcius, and F represents degrees fahrenheit.
A). 165 degrees C
B). 183 degrees C
C). 201 degrees C
D). 535 degrees C
Solve:
C = 5/9(F - 32)
Simplify both sides:
C = 5/9(329 - 32) = 0
Simplify:
5/9
Equation at end of step 1:
C - (5/9 * 297) = 0
C - 165 = 0
Solve single variable:
C - 165 = 0
Add 165 to both sides:
C = 165
Therefore, Your answer would be, Letter Choice (A), (C = 165 degrees C
Hope that helps!!!!! Have a great day!!!!! : )
