Answer:
V=5.333cubit unit
Step-by-step explanation:
this problem question, we are required to evaluate the volume of the region bounded by the paraboloid z = f(x, y) = 3x² + y² and the square r: -1≤ x ≤ 1, -1 ≤ y ≤ 1
The question can be interpreted as z = f(x, y) = 3x² + y² and the square r: -1≤ x ≤ 1, -1 ≤ y ≤ 1 and we are told to evaluate the volume of the region bounded by the given paraboloid z
The volume V of integral evaluated along the limits of x and y for the 2-D figure, can be evaluated using the expression below
V = ∫∫ f(x, y) dx dy then we can now substitute and integrate accordingly.
CHECK THE ATTACHMENT BELOW FOR DETAILED EXPLATION:
There is nothing in the space. If there were, then the space would not be blank.
It must be ≤ instead of ≥.
y ≤ - 3·x + 4
Answer:
It is subtracting 4 each time, if it were to go on it would go -16 -20 -24 -28 -32 -36 -40 -44 -48 -52 etc
Step-by-step explanation: