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pav-90 [236]
2 years ago
13

The owner of a new coffee shop is keeping track of how much each customer spends (in dollars). A random number table was used to

generate a random sample of 20 pieces of data. The dot plot below shows the twenty pieces of data.
Based on the data in the dot plot, what would you expect the mean of the sample to be? EXPLAIN YOUR REASONING.

Mathematics
1 answer:
frosja888 [35]2 years ago
4 0
I expect the mean of the sample to be 5.00
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Can someone help plsss!
Roman55 [17]

Well the y-intercept is +2

And the slope of the blue line is 1/2

So y=1/2x+2

Slope is rise/run (up then ((right)))

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Max bought a package of hamburger that weighs 5 1/3 pounds. He needs 1/3 of that amount for a recipe.
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FREE BRAINLY TO THE CORRECT ANSWER!!
Lyrx [107]

Answer: -3

Step-by-step explanation:

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8 0
3 years ago
At what rate per annum ci will RS 2000 amount to RS 2315.35 in 3 years
Mashutka [201]

<u>ANSWER: </u>

Rate per annum at which CI will amount from RS 2000 to RS 2315.35 in 3 years is 5%

<u>SOLUTION: </u>

Given,  

P = RS 2000

C.I = RS 2315.35

T = 3 years

We need to find the rate per annum. i.e. R = ?

We know that,  

When interest is compound Annually:

Amount $=\mathrm{P}\left(1+\frac{\mathrm{R}}{100}\right)^{n}$

Where p = principal amount

r = rate of interest

n = number of years

$2315.35=2000 \times\left(1+\frac{R}{100}\right)^{3}$

$\left(1+\frac{R}{100}\right)^{3}=\frac{2315.35}{2000}$

$\left(1+\frac{R}{100}\right)^{3}=1.157$

$1+\frac{R}{100}=\sqrt[3]{1.157}$

$1+\frac{R}{100}=1.0500$

$\frac{R}{100}=1.05-1$

$\frac{R}{100}=0.05$

R = 5%

Hence, rate per annum is 5 percent.

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