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Vera_Pavlovna [14]
3 years ago
9

What is the range of this data set? 64º, 72º, 74º, 68º, 70º, 68º, 68º, 75º and 44º

Mathematics
2 answers:
d1i1m1o1n [39]3 years ago
7 0

Answer: 31

Step by step explanation:

order your numbers from lowest to highest

find the biggest number (in your example, 75)

then subtract the smallest number (in your example 44)

so for example it would be 75-44

then you got your answer! hope this helped

Lina20 [59]3 years ago
4 0

Answer:

The range is found by subtracting the lowest number (44) from the highest number (75).  75-44=31  So your range is 31

Step-by-step explanation:

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Question 9: Please help, what would be the length of the image of the segment GH?
shepuryov [24]

Answer:

<u><em></em></u>

  • <u><em>The length of the image of the segment GH would be 5 units.</em></u>

Explanation:

You can use the <em>center of dilation</em> as your origin of coordintes.

Thus, the <em>point H</em> would have coordinates (0,0) and the <em>point G</em> (-1,0).

A <em>dilation</em> multiplies the coordinates by the <em>scale factor</em>. Hence:

  • H = (0,0) → H' = 5 × (0,0) = (0,0)
  • G = (-1,0) → G] = 5 × (-1, 0) = (-5, 0)

Thus, the length of the image of segment GH would be the distance from 0 to -5 in a number line, which is 5.

3 0
3 years ago
Read 2 more answers
PLSS HELP ME WITH THIS
kolbaska11 [484]

Answer:

127

Step-by-step explanation:

400+1495=1895

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8 0
3 years ago
What is the number that not the same in a fish
stira [4]

Answer:

2

Step-by-step explanation:

6 0
2 years ago
Imagine that you need to compute e^0.4 but you have no calculator or other aid to enable you to compute it exactly, only paper a
labwork [276]

Answer:

0.0032

Step-by-step explanation:

We need to compute e^{0.4} by the help of third-degree Taylor polynomial that is expanded around at x = 0.

Given :

e^{0.4} < e < 3

Therefore, the Taylor's Error Bound formula is given by :

$|\text{Error}| \leq \frac{M}{(N+1)!} |x-a|^{N+1}$   , where $M=|F^{N+1}(x)|$

         $\leq \frac{3}{(3+1)!} |-0.4|^4$

         $\leq \frac{3}{24} \times (0.4)^4$

         $\leq 0.0032$

Therefore, |Error| ≤ 0.0032

4 0
3 years ago
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Luba_88 [7]
The first two is wrong, the last two is one of the right ones, I think it’s c
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