This equation if finding x would be 88
Kx-3y=k
y=4x+1 ( we will put it in 1st equation )
kx - 3 (4x+1)=k
kx - 12 x - 3 =k
kx - 12 x = k+3
x(k-12) = k+3
x=
Also y=
We can not divide with zero.
k-12=0
k=12For k= 12 equations have no solutions.
Answer:
see explanation
Step-by-step explanation:
Given
f(x) = x² - 6x + 8 and g(x) = x + 2
To solve f(x) = g(x), equate the right sides, that is
x² - 6x + 8 = x + 2 ← subtract x + 2 from both sides
x² - 7x + 6 = 0 ← in standard form
(x - 1)(x - 6) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 1 = 0 ⇒ x = 1
x - 6 = 0 ⇒ x = 6
These solutions can be verified from the tables, that is
f(x) = g(x) = 3 ← when x = 1
f(x) = g(x) = 8 ← when x = 6