Answer:
25
Step-by-step explanation:
We require to solve for n, hence
n(n + 1) = 325
multiply both sides by 2 to eliminate the fraction
n(n + 1) = 650
n² + n = 650
subtract 650 from both sides to have equation in standard form
n² + n - 650 = 0 ← in standard form
(n + 26)(n - 25) = 0 ← in factored form
equate each factor to zero and solve for n
n + 26 = 0 ⇒ n = - 26
n - 25 = 0 ⇒ n = 25
however, n > 0 ⇒ n = 25
Answer:
p(x) = 7x - 20
Step-by-step explanation:
A company makes a profit selling goods when the revenue taken in from the sales is greater than the cost of those goods: p(x) = r(x) - c(x) > 0.
In this case the revenue function is r(x) = 12x; the cost function is c(x) = 5x + 20, and the profit function is p(x) = 12x - (5x + 20), or:
p(x) = 12x - 5x - 20, or
p(x) = 7x - 20
Answer:
Step-by-step explanation:
The principal was compounded monthly. This means that it was compounded 12 times in a year. So
n = 12
The rate at which the principal was compounded is 4%. So
r = 4/100 = 0.04
The formula for compound interest is
A = P(1+r/n)^nt
A = total amount in the account at the end of t years. The total amount is given as $100000.
1) When t is 1,
100000 = P(1+0.04/12)^12×1
100000 = P(1+0.0033)^12
100000 = P(1.0033)^12
P = 100000/1.04
P = $96154
2) When t is 10
100000 = P(1+0.04/12)^12×10
100000 = P(1+0.0033)^120
100000 = P(1.0033)^120
P = 100000/1.485
P = $67340
3) When t is 20
100000 = P(1+0.04/12)^12×20
100000 = P(1+0.0033)^240
100000 = P(1.0033)^240
P = 100000/2.2
P = $45455
4) When t is 30
100000 = P(1+0.04/12)^12 × 30
100000 = P(1+0.0033)^360
100000 = P(1.0033)^360
P = 100000/3.274
P = $30544
5) When t is 40
100000 = P(1+0.04/12)^12 × 40
100000 = P(1+0.0033)^480
100000 = P(1.0033)^480
P = 100000/4.862
P = $20568
6)When t is 50
100000 = P(1+0.04/12)^12 × 50
100000 = P(1+0.0033)^600
100000 = P(1.0033)^600
P = 100000/7.22
P = $13850
Answer:
x = -1
Step-by-step explanation:
3x + 1 = -2
Subtract 1 from both sides.
3x = -2 - 1
Simplify -2 - 1 to 3.
3x = -3
Divide both sides by 3.
x = -1
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