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Rudik [331]
3 years ago
8

Solve the following x^2-2x-24=0 X^2-11+18=0

Mathematics
1 answer:
Marrrta [24]3 years ago
6 0

Answer:

x=-11

Step-by-step explanation:

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SELECT ALL The Points that are on the Graph of the line 3x + 2y = 28 (:
Oksana_A [137]
<h2>Answer:</h2>

<h3>(0,14) and (2,11)</h3>

<h2>Step-by-step explanation:</h2>

points are on the graph of the line:-

\tt{3x+2y=28  } ⠀

we get,

\rightsquigarrow \tt{ 2y=28-3x } ⠀

\rightsquigarrow \tt{y=\dfrac{28-3x}{2}  } ⠀

In,(0,14)

If we put the value ,x=0

y=\tt{\dfrac{ 28-3×0}{2}=\dfrac{28}{2}=14 }

So,we get one point,(0,14)✔

In,(2,11)

If we put ,x=2

y=\tt{\dfrac{28-3×2}{2}=\dfrac{28-6}{2}=\dfrac{22}{2}=11  }

so,we get another point (2,11)✔

in other given ponts{(1,12),(4,9),(8,4)},It is impossible. ⠀ ⠀

5 0
3 years ago
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If mÃc=170° Find mLB
kenny6666 [7]

Answer:

∠ B = 85°

Step-by-step explanation:

the inscribed angle B is half the measure of its intercepted arc AC , then

∠ B = \frac{1}{2} × 170° = 85°

8 0
1 year ago
What is the area of the sector with a central angle of 49° and a radius of 11 cm? Use 3.14 for pi and round your final answer to
olga_2 [115]

Answer:

\boxed{\text{51.71 cm}^{2}}

Step-by-step explanation:

If the angle θ is in radians, the formula for the area (A) of a sector of a circle is

A = ½r²θ

If θ is in degrees

A = \dfrac{1}{2}r^{2}\theta \times \dfrac{\pi \text{ rad}}{180^{\circ}}= \pi r^{2}\times\dfrac{\theta }{360}

Data:

θ = 49°

r = 11 cm

Calculation:

\begin{array}{rcl}A& = &3.14\times 11^{2}\times\dfrac{49}{360}\\\\ & = &3.14 \times 121 \times 0.1361\\ & = & \mathbf{51.71}\\\end{array}\\\text{The area of the sector is }\boxed{\textbf{51.71 cm}^{2}}

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3 years ago
I need help with my algebra hw
Y_Kistochka [10]

Answer:

well?

Step-by-step explanation:

5 0
3 years ago
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Can a triangle be formed with the sides lengths of 8 cm, 5 cm and 13 cm?
Anni [7]

The rule says that the sum of any two sides has to be smaller than the third side so, no it can't

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