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3 years ago

Solve and write equation in Slope intercept

Mathematics

1 answer:

Semmy [17]3 years ago

3 0

Answer:

Step-by-step explanation:

1. is y= 3 x +8

-3 x + y - 8= 0

y = 3x+ 8

2. is in the pictures

3 X + 5 y - 10 = 0

Real solution:

y = 2 - (3 X)/5

Solution:

y = 2 - (3 X)/5

Integer solution:

X = 5 n, y = 2 - 3 n, n element Z

Solution for the variable y:

y = 1/5 (10 - 3 X)

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If the hypotenuse of a right triangle is 15 inches and one leg is 9 inches, the measure of the angle between these sides, rounde

katrin [286]

If the angle is x we have

cos x = 9/15 = 0.6

x = 53 degrees

So it's false.

3 0

4 years ago

Jasmine borrowed $15,000 for 8 years and she paid $6,600 in interest. What was the interest rate for Jasmine's loan?

weeeeeb [17]

Answer:

5.5%

Step-by-step explanation:

To find the interest rate, use the equation: I = prt

I = Interest = $6,600

p = principal = $15,000

r = rate = unknown

t = time = 8 years

Now plug the numbers into the equation.

6,600 = 15,000 * r * 8

6,600 = 120,000 * r

Now isolate the variable by dividing both sides of the equation by 120,000.

0.055 = r

Now change the rate to a percent by moving the decimal point 2 digits to the right.

5.5% = r OR r = 5.5%

4 0

3 years ago

Add.Your answer should be an expandedpolynomial in standard form.(-4° - 5y + 16) + (4y2 – y +9) =

pav-90 [236]

The expression is,

$(-4y^3-5y+16)+(4y^2-y+9$

Remove the brackets and put terms with same exponents together.

$undefined$

8 0

1 year ago

3) Cory is standing on a cliff that is 48 feet above the ground. He throws a rock in to the air. The height, h, of the rock

Nadusha1986 [10]

Answer:

a) The initial height of the rock is of 48 feet.

b) It takes 1 seconds for the rock to reach maximum height.

c) The rock's maximum height is 50 feet.

d) It takes 6 seconds for the rock to land on the ground.

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

$f(x) = ax^{2} + bx + c$

It's vertex is the point $(x_{v}, f(x_{v})$

In which

$x_{v} = -\frac{b}{2a}$

If a<0, the vertex is a maximum point, that is, the maximum value happens at $x_{v}$ , and it's value is $f(x_{v})$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

The height of the ball after t seconds, in feet, is given by:

$h(t) = -2t^2 + 4t + 48$

Which is a quadratic equation with $a = -2, b = 4, c = 48$

a) What is the initial height?

This is $h(0) = 48$ . So the initial height of the rock is of 48 feet.

b) How many seconds does it take to reach the maximum height?

This is the value of t at the vertex. So

$t_{v} = -\frac{b}{2a} = -\frac{4}{2(-2)} = 1$

It takes 1 seconds for the rock to reach maximum height.

c) What is the rock's maximum height?

This is the height of the ball after 1 second. So

$h(1) = -2(1)^2 + 4(1) + 48 = 50$

The rock's maximum height is 50 feet.

d) How many seconds does it take to for the rock to land on the ground?

This is t for which $h(t) = 0$ , so we solve the quadratic equation.

$\bigtriangleup = (4)^2-4(-2)(48) = 400$

$t_{1} = \frac{-4 + \sqrt{400}}{2*(-2)} = -4$

$t_{2} = \frac{-4 - \sqrt{400}}{2*(-2)} = 6$

Time is a positive measures, so it takes 6 seconds for the rock to land on the ground.

5 0

3 years ago

the basketball team spends 20 minutes running laps and at least 15 minutes discassing plays. Practice lasts one hour and 45 minu

ladessa [460]

20+15=/35-45
Is this the type of answer you were looking for?

3 0

4 years ago