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zzz [600]
3 years ago
7

I need help with geometry

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
7 0

9514 1404 393

Answer:

  C.  26

Step-by-step explanation:

The two marked angles are "vertical angles." They are congruent.

  x +20 = 3x +8 . . . . . congruent angles have the same measure

  12 = 2x . . . . . . . . . subtract x+8 from both sides

  6 = x . . . . . . . . . divide by 2

  ∠PTQ = (x+20)° = (6+20)° = 26°

BARSIC [14]3 years ago
6 0

Answer:

Solutions given:

we have

<RTS=PTQ[vertically opposite angle are equal]

so

3x+8=x+20°

3x-x=20-8

2x=12

x=12/2=6

x=6

m<PTQ=6+20=26°

<u>option</u><u> </u><u>c</u><u>.</u><u>2</u><u>6</u><u>.</u>

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Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

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h(x)=ax(x-7)             ...(i)

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The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

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The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)

h(1.5)=-(0.5)(-5.5)

h(1.5)=2.75

Since h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.

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3 years ago
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