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3 years ago

One positive number is 9 more than twice another. If their product is 731, find the numbers.

Mathematics

2 answers:

Korolek [52]3 years ago

8 0

Answer:

361

Step-by-step explanation:

mamaluj [8]3 years ago

8 0

The answer is 361 yupppp

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How many people can Brian pay for (including himself) while staying within the limitations of his budget?

pishuonlain [190]

Answer:

54$

Step-by-step explanation:

5 0

3 years ago

Refer to the random sample of customer order totals with an average of $78.25 and a population standard deviation of $22.50. a.

zysi [14]

Answer:

a) $78.25- 1.64 \frac{22.50}{\sqrt{40}}= 72.416$

$78.25+ 1.64 \frac{22.50}{\sqrt{40}}= 84.084$

b) $78.25- 1.64 \frac{22.50}{\sqrt{75}}= 73.989$

$78.25+ 1.64 \frac{22.50}{\sqrt{75}}= 82.511$

c) For this case when we increase the sample size the margin of error would be lower and then the interval would be narrower

d) $ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

Solving for n we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

And replacing the info we have:

$n=(\frac{1.640(22.50)}{5})^2 =54.46 \approx 55$

Step-by-step explanation:

Part a

For this case we have the following data given

$\bar X = 78.25$ represent the sample mean for the customer order totals

$\sigma =22.50$ represent the population deviation

$n= 40$ represent the sample size selected

The confidence level is 90% or 0.90 and the significance level would be $\alpha=0.1$ and $\alpha/2 = 0.05$ and the critical value from the normal standard distirbution would be given by:

$z_{\alpha/2}=1.64$

And the confidence interval is given by:

$\bar X -z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$78.25- 1.64 \frac{22.50}{\sqrt{40}}= 72.416$

$78.25+ 1.64 \frac{22.50}{\sqrt{40}}= 84.084$

Part b

The sample size is now n = 75, but the same confidence so the new interval would be:

$78.25- 1.64 \frac{22.50}{\sqrt{75}}= 73.989$

$78.25+ 1.64 \frac{22.50}{\sqrt{75}}= 82.511$

Part c

For this case when we increase the sample size the margin of error would be lower and then the interval would be narrower

Part d

The margin of error is given by:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

Solving for n we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

And replacing the info we have:

$n=(\frac{1.640(22.50)}{5})^2 =54.46 \approx 55$

3 0

3 years ago

Q8: Identify the graph of the equation. What is the angle of rotation for the equation?

Allisa [31]

Answer:

B. hyperbola, 45°

Step-by-step explanation:

This is rotation in quadratic equations

Perform elimination of xy term

Ax² +B xy+Cy²+Dx+Ey+F=0

Rotation of axes of the coordinates through angle θ to satisfy

Cot 2θ =(A-C)/B

But B≠ 0 and A=C=0

Answer will be hyperbola, 45°

3 0

3 years ago

If 11 runners are participating in a race, how many different ways can there be first and second place runners?

MrRa [10]

Only first and second place runners:
11*10=110 ways

Hope that helped.

6 0

4 years ago

If cot(θ)= 5 12 and 0°<θ<90°, what is sin(θ)?

Ivahew [28]

Using,
1+cot^2 x = csc^2 x
1+ (5/12)^2 = csc^2 x
1+25/144 = csc^2 x = (144+25)/144 = 169/144
csc x = sqrt (169/144) = 13/12

sin x = 1/ csc x = 1/(13/12) = 12/13 is your answer :)

5 0

4 years ago