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3 years ago

Help me...............:..

Mathematics

1 answer:

Andrei [34K]3 years ago

6 0

It's saying that both of the shapes are equal to each other. It wants you to compare them so it would be like AB = SR and such

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The table below shows the results of a survey of 1000 American college students and their age breakdown. Use the table to answer

mel-nik [20]

Answer:

Step-by-step explanation:

3 0

3 years ago

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A quarterback throws a football to a teammate. The football is 6.5ft above the ground when it leaves the quarterback's hand. His

sergejj [24]

Answer:

y = - 16t² + 55.6t + 6

Step-by-step explanation:

Using y - y₀ = vt - 1/2gt² where g = 32 ft/s², and v the velocity of the football

So y = y₀ + vt - 1/2 × (32 ft/s²)t²

y = y₀ + vt - 16t² where y₀ = 6.5 ft

y = 6 + vt - 16t²

Now, when t = 3.5 s, that is the time the teammate catches the ball after the quarterback throws it, y = 5 ft. Substituting these into the equation, we have

5 = 6.5 + v(3.5 s) - 16(3.5 s)²

5 = 6.5 + 3.5v - 196

collecting like terms, we have

5 - 6.5 + 196 = 3.5v

194.5 = 3.5v

v = 194.5/3.5 = 55.57 ft/s ≅ 55.6 ft/s

So, substituting v into y, our quadratic model is

y = 6 + 55.6t - 16t²

re-arranging, we have

y = - 16t² + 55.6t + 6

6 0

3 years ago

A pilot is traveling at a height of 30,000 feet above ground she looks down at a angle of depression of 6 and spots runway as me

sukhopar [10]

Distance between runway and pilot position along the ground is 285430.9336 feet that is 53.9464 miles.

<h3><u>Solution:</u></h3>

Given that

Height of position of pilot from the ground = 30000 feet

Angle of depression when he looks down at runway = 6o

Need to measure along the ground, distance between runway and pilot that is horizontal distance between runway and pilot.

Consider the figure attached below

D represents position of runway.

P represents position of pilot.

PG represents height of position of pilot from the ground that means PG = 30000 feet

PH is virtual horizontal line and HPD is angle of depression means ∠ HPD = 6 degree

AS DG and HP are horizontals, so DG is parallel to HP.

=> ∠ HPD =∠ PDG = 6 degree [ Alternate interior angle made by transversal PD of two parallel lines ]

We need to calculate DG

Consider right angles triangle PGD right angles at G

$\text {As } \tan x=\frac{\text { Perpendicular }}{\text { Base }}$

$\tan \angle \mathrm{PDG}=\frac{\mathrm{PG}}{\mathrm{GD}}$

$\begin{array}{l}{=>\mathrm{GD}=\frac{\mathrm{PG}}{\tan \angle \mathrm{PDG}}} \\\\ {=>\mathrm{GD}=\frac{30000}{\tan 6^{\circ}}=285430.9336}\end{array}$