Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.
Given:
Perimeter of the floor of a room = 18 metre
Height of the room = 3 metre
To find:
The area of 4 walls of the room.
Solution:
We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.
The curved surface area of the cuboid is
Where, h is height, l is length and b is breadth.
Perimeter of the rectangular base is 2(l+b). So,
Putting the given values, we get
Therefore, the area of 4 walls of the room is 54 sq. metres.
Answer:
NCA = GRU
Step-by-step explanation:
Since triangle CAN = triangle RUG
This means
C=R
A=U
N = G
We can change the order of the letters for the triangle in the first, but then they have to be corresponding in the second
ANC = UGR
NCA = GRU
ACN = URG
CNA= RGU
Answer:
Step-by-step explanation:
2x - y > 4 ⇒ y < 2x - 4
x + y < - 1 ⇒ y < - x - 1
The athlete's average speed was 300 meters/minute.
<h3>How to calculate the speed of the athlete?</h3>
To calculate the speed of the athlete we must perform the following operations.
Divide the distance into the total time:
Transform the value from seconds to minutes, for which we must multiply 5 by 60 because each minute is made up of 60 seconds.
- 5m/sec × 60sec = 300m/min
According to the above, the average speed of the athlete is 300m/min.
Learn more about speed in: brainly.com/question/7359669
1. y₁ = 70x
2. y₂ = 55x
Solve y₁ - y₂ for x = 11.
