Answer:
Step-by-step explanation:
A. y-Intercept of ƒ(x)
ƒ(x) = x² - 4x + 3
f(0) = 0² - 4(0) + 3 = 0 – 0 + 3 = 3
The y-intercept of ƒ(x) is (0, 3).
If g(x) opens downwards and has a maximum at y = 3, it's y-intercept is less than (0, 3).
Statement A is TRUE.
B. y-Intercept of g(x)
Statement B is FALSE.
C. Minimum of ƒ(x)
ƒ(x) = x² - 4x + 3
a = 1; b = -4; c = 3
The vertex form of a parabola is
y = a(x - h)² + k
where (h, k) is the vertex of the parabola.
h = -b/(2a) and k = f(h)
h = -b/2a = -(-4)/(2×1 = 2
k = f(2) = 2² - 4×2 + 3 =4 – 8 +3 = -1
The minimum of ƒ(x) is -1. The minimum of ƒ(x) is at (2, -1).
Statement C is FALSE.
D. Minimum of g(x)
g(x) is a downward-opening parabola. It has no minimum.
Statement D is FALSE
Answer:
c*2=a2+b*2
c*2=3*2+6*2
c*2=9+36
c=root of 45
root of 45*8(sincethere are 8 sides if roots of45
Answer:
y=-3x-3
Step-by-step explanation:
To get a perpendicular line you take the negative reciprocal of the slope, so in this case it would equal -3. Now use point-slope form to get your equation. Point slope form says that y-y1=m(x-x1) where m is your slope and x1 and y1 are the points that the graph passes through. So in this case x1=-3, y1=6, and m=-3. This gives you the equation y-6=-3(x+3). Distribute to y-6=-3x-9, and finally add 6 to both sides to get y=-3x-3
I assume the equation is
then let .
The right side is real-valued and positive, and only on the left side do we have an imaginary term, which tells us
Then
but again we omit the negative solution, so that
Answer:
The scale used on his map is <u>150 miles : 2 inches</u>.
Step-by-step explanation:
Given:
Ted knows the actual distance between two cities is 150 miles. His map shows a distance of 2 inches between these cities.
Now, to find the scale Ted used on his map.
The actual distance Ted know between two cities = 150 miles.
The distance on map between these cities = 2 inches.
So, to get the scale used on his map:
Therefore, the scale used on his map is 150 miles : 2 inches.