Question

Please help me fast i will give first answer brainliest!!​

Answer 1

Answer:

see below

Step-by-step explanation:

f(x) = 2x^2 +4x-16

Factor out 2

f(x) = 2 (x^2 +2x) -16

Complete the square inside the parentheses

Take the coefficient of x, divide by 2 and square it

(2/2)^1

f(x) = 2 ( x^2+2x+1   -1 ) -16

Bring the -1 outside the parentheses

f(x) = 2(x^2+2x+1)-2 -16

f(x) = 2(x+1)^2 - 18

This is in vertex form

y = a(x-h)^2 + k  where ( x,k) is the vertex

f(x) = 2(x - -1)^2 - 18

The vertex is (-1,-18)

Answer 2

Answer:

(-1,-18) is the coordinate of the vertex.

Step-by-step explanation:

We can obtain the vertex by taking the derivative and equating it to zero. I know this because the the slope of the tangent line at the vertex has to be equal to zero.

the derivative would be 4x + 4 = 0, where x = -1.

Plugging x into the original value we will end up with the y coordinate.

Hope this helps.