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3 years ago

The graph shown below is a scatter plot:

Mathematics

1 answer:

Verdich [7]3 years ago

8 0

I don’t see a point so how am I supposed to answer

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"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen

Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± $Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ ]

Where

p' is the sample proportion/point estimator of the population proportion

$Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ is the margin of error (d) of the confidence interval.

$Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648$

$d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$

$d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }$

$(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}$

$n*(d*Z_{1-\alpha /2})^2= p'(1-p')$

$n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}$

$n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}$

n= 147.28 ≅ 148 boxes.

I hope it helps!

3 0

3 years ago

PLEASE ANSWER IT'S IN THE PICTURE I WILL MARK BRAINLIEST IF YOU'RE CORRECT!

harkovskaia [24]

Answer:

It is possible for a set of data values to have more than one mode. If there are two data values that occur most frequently, we say that the set of data values is bimodal. If there is no data value or data values that occur most frequently, we say that the set of data values has no mode.

Step-by-step explanation:

7 0

3 years ago

Mrs carter manages a pizza parlor the average daily cost is 40 $ plus 52 $ to pay each employee it also cost 2$ to make each piz

Shtirlitz [24]

Total costs: 40 + (7*52) + (42*2) = 488

4 0

3 years ago

30 POINTS NO CAP PLEASE HELP ME NEED RIGHT ANSWER

Cloud [144]

I think it’s 14/-28 which simplifies to 7/-14 which then goes to 1/-2. i hope that helped!

4 0