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Lapatulllka [165]
3 years ago
8

A degree is larger than 30 arc minutes. ...? true or false

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
7 0
It is a completely true statement that a <span>degree is larger than 30 arc minutes. The correct option among the two options that are given in the question is the first option. 30 arc minutes is almost equal to 1/2 degree. I hope that this is the answer that you were looking for and the answer has actually come to your great help.</span>
Roman55 [17]3 years ago
7 0

Answer:

True  

Step-by-step explanation:

Given : Statement - 'A degree is larger than 30 arc minutes'.

To find : True or False ?

Solution :

We know that,

1 degree is 1^\circ=\frac{1}{360} of a circle

1 arc minute is 1^'=(\frac{1}{60})^\circ of degree.

So, 30 arc minutes is 30^'=(\frac{30}{60})^\circ of degree.

30 arc minutes is 30^'=(\frac{1}{2})^\circ of degree.

Which clearly means,

1^\circ>(\frac{1}{2})^\circ

1^\circ>30^'

Therefore, The given statement is true.

'A degree is larger than 30 arc minutes'.

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Area of a triangle is given by the formula A=1/2 bh. The area of the triangle shown to the right is 56 sq. units. Find its base
Westkost [7]
Given

base=2x+6
height=x+4

and
area=56 square units

56=1/2 times (2x+6) times (x+4)
times bot sides by 2
112=(2x+6)(x+4)
expand
112=2x²+14x+24
divide both sides by 2
56=x²+7x+12
minus 56 both sides
0=x²+7x-44
factor
waht 2 numbers mulitply to get -44 and add to get 7
11 and -4
0=(x-4)(x+11)
set to 0

x-4=0
x=4

x+11=0
x=-11
false, measures can't be negative

x=4


height=x+4
height=4+4=8


base=2x+6
base=2(4)+6=8+6=14



x=4 and base=14 and height=8

8 0
3 years ago
Can someone help me with number 7 and 8 pls​
Leto [7]

8.romb

Step-by-step explanation:

thats all I know

5 0
3 years ago
Read 2 more answers
Flying with the wind, a small plane flew 404 mi in 2 h. Flying against the wind, the plane could fly only 386 mi in the same amo
Alika [10]

Answer: rate of the plane is 197.5 mph

rate of wind is 4.5 mph

Step-by-step explanation:

Let x represent the rate of the plane in calm air.

Let y represent the rate of the wind.

Flying with the wind, a small plane flew 404 mi in 2 h. This means that the total speed with which the plane flew is (x + y) mph.

Distance = speed × time

Distance travelled by the plane while flying with the wind is

404 = 2(x + y)

Dividing both sides of the equation by 2, it becomes

202 = x + y- - - - - - - - - - - 1

Flying against the wind, the plane could fly only 386 mi in the same amount of time. This means that the total speed at which the plane flew is (x - y) mph.

Distance = speed × time

Distance travelled by the plane while flying against the wind is

386 = 2(x - y)

Dividing both sides of the equation by 2, it becomes

193 = x - y- - - - - - - - - - - 2

Adding equation 1 to equation 2, it becomes

395 = 2x

x = 395/2

x = 197.5

Substituting x = 197.5 into equation 1, it becomes

202 = 197.5 + y

y = 202 - 197.5

y = 4.5

3 0
3 years ago
3x=5x-9 pls help ?!!?!?!?!?!?!?!?!??!!?1/
lbvjy [14]

Answer: x = 4.5

Step-by-step explanation:

1) Reorder the terms:

3x = -9 + 5x

2) Solving

3x = -9 + 5x

3) Solving for variable 'x'.

4) Move all terms containing x to the left, all other terms to the right.

5) Add '-5x' to each side of the equation.

3x + -5x = -9 + 5x + -5x

6) Combine like terms: 3x + -5x = -2x

-2x = -9 + 5x + -5x

7) Combine like terms: 5x + -5x = 0

-2x = -9 + 0

-2x = -9

8) Divide each side by '-2'.

x = 4.5

9) Simplifying

x = 4.5

6 0
3 years ago
Read 2 more answers
Can someone please help me with this?
dsp73

Answer:

S_{13} = 403

Step-by-step explanation:

the sum to n terms of an arithmetic series is

S_{n} = \frac{n}{2} (a + l) ← a is the first term and l the last term

here a = - 5 and l = 67 , then

S_{13} = \frac{13}{2} (- 5 + 67) = 6.5 × 62 = 403

3 0
2 years ago
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