Answer:
The work done in stretching the spring is 8 lb.ft
Step-by-step explanation:
Given;
Applied force, F = 192 lb
extension of the spring, x = 3 ft
Determine the spring constant from the applied force and extension;

When the spring is stretched 6 inches beyond its natural length, the work done is calculated as follows;
x = 6 inches = 0.5 ft

Therefore, the work done in stretching the spring is 8 lb.ft
Answer:
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Step-by-step explanation:
Answer:
Step-by-step explanation:
6
Answer:
A = 153.94 sq mi
Step-by-step explanation:
In this scenario, we would be starting from the center point and searching the area of a square since the distance in every direction would the same 7 mi. This 7-mile distance would be our radius in this scenario. We now need to use the formula for the Area of a circle to calculate the search area. This formula is the following
A = 
A = 
A = 
A = 153.94 sq mi
A total of 153.94 square miles must be searched.
When you simplify the expression 1/1+cot^2x the final product is C. sin^2 (x).
Hope this helps!