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3 years ago

While I was trying to make something my microwave exploded

Mathematics

2 answers:

diamong [38]3 years ago

6 0

Answer:

OMG!!!! WHAT WERE YOU TRYING TO MAKE

marshall27 [118]3 years ago

5 0

Answer: dangg

Step-by-step explanation:

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f(x) is a quadratic function with x-intercepts at (−1, 0) and (−3, 0). If the range of f(x) is [−4, [infinity]) and g(x) = 2x^2

iren2701 [21]

Answer with Step-by-step explanation:

We are given that function f(x) which is quadratic function.

x -intercept of function f(x) at (-1,0) and (-3,0)

x-Intercept of f means zeroes of f

x=-1 and x=-3

Range of f =[-4, $\infty$ )

g(x)= $2x^2+8x+6=2(x^2+4x+3)$

$g(x)=0$

$2(x^2+4x+3)=0$

$x^2+4x+3=0$

$x^2+3x+x+3=0$

$x(x+3)+1(x+3)=0$

$(x+1)(x+3)=0$

$x+1=0\implies x=-1$

$x+3=0\implies x=-3$

Therefore, x-intercept of g(x) at (-1,0) and (-3,0).

Substitute x=-2

$g(-2)=2(-2)^2+8(-2)+6=8-16+6=-2$

$g(x)=2(x^2+4x)+6$

$g(x)=2(x^2+2\times x\times 2+4-4)+6=2(x^2+2\times x\times 2+4)-8+6$

$g(x)=2(x+2)^2-2$

By comparing with the equation of parabola

$y=a(x-h)^2+k$

Where vertex=(h,k)

We get vertex of g(x)=(-2,-2)

Range of g(x)=[-2, $\infty$ )

Zeroes of f and g are same .

But range of f and g are different.

Range of f contains -3 and -4 but range of g does not contain -3 and -4.

f and g are both quadratic functions.

3 0

3 years ago

Please help me with this question.

Sav [38]

Answer:

-2; -7

Step-by-step explanation:

Hello, the graph is split in two lines, right?

Go to the first line at the left and move to the right until you reach the end of the line, which is for x = -1,

*** This is the meaning of x tending to

$(-1)^{-}$ ***

which value can you see for the y-axis? $\boxed{-2}$

Now, go to the second line at the right and move to the left until you reach the end of the line, which is for x = -1,

*** This is the meaning of x tending to

$(-1)^{+}$ ***

which value can you see for the y-axis?

$\boxed{-7}$

Thanks

7 0

3 years ago

How to do the monomials

Cerrena [4.2K]

<u>Given</u>:

The given monomial expression is $\frac{16 y^{8}}{4 y^{2}}$

We need to simplify the given monomial expression.

<u>Simplification:</u>

Let us simplify the given expression.

Dividing the numbers 16 and 4, we get;

$\frac{4 y^{8}}{y^{2}}$

Let us apply the exponent rule $\frac{x^{a}}{x^{b}}=x^{a-b}$ in the above expression.

Thus, we get;

$4 y^{8-2}$

Subtracting the numbers in the numerator of the above expression, we get;

$4 y^{6}$

Thus, the simplified expression is $4 y^{6}$

8 0

3 years ago

Please help. i need this solved

SIZIF [17.4K]

Jsmssjsjssj zjejejejsjeiriritj

3 0

3 years ago

The right cylinder in the diagram has a volume of 450 cm3. The other cylinder has a slant length of 10 cm, but the same base are

mezya [45]

A tilted or slanted cylinder has the same volume as its equivalent right cylinder, provided that
(a) the two bases of the tilted cylinder are parallel,
(b) the base areas of the tilted and right cylinders are equal,
(c) the vertical height of the right and tilted cylinders are equal.

This fact can be verified by slicing the tilted cylinder into thin, flat washers, as in integral calculus.

Because all 3 conditions are satisfied, the volume of the tilted cylinder is 450 cm³.

Answer: 430 cm³

5 0

3 years ago