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3 years ago

Polygon EFGH is a reflection of ABCD. Which of the following angle are congruent

Mathematics

2 answers:

Allisa [31]3 years ago

8 0

Angle B and F, the second option

melomori [17]3 years ago

5 0

Answer:

B) ∠B and ∠F

Step-by-step explanation:

Here the polygon ABCD reflected over the y-axis and got the polygon EFGH.

When the polygons are reflected the measure of angles will not be changed and only the coordinates will be changed.

Here polygon ABCD is reflected over y-axis. So only the sign of the x -coordinate will change.

Let's see them.

A = (3, -1) ---> E = (-3, -1)

B = (5, -3) ---> F(-5, -3)

C = (4, -6) ----> G(-4, -6)

D = (1, -4) ----> H(-1, -4)

You can see the only x coordinate's sign changed.

Therefore, The ∠B and ∠F is true.

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How many 5 1/4 ounce glasses can be completely filled from a 33 1/2 ounce container of juice?

geniusboy [140]

You need to divide.
We are dividing the mixed numeral 33 1/21 by the mixed numeral 5 1/4.

(33 1/2 ) / (5 1/4) =

The first step is to change the two mixed numerals into improper fractions.
33 1/2 = 67/2, and 5 1/4 = 21/4

= (67/2) / (21/4)

Now we are dividing the fraction 67/2 by the fraction 21/4.
To divide a fraction by a fraction, rewrite the first fraction, change division intro multiplication, and flip the second fraction. To divide 67/2 by 21/4, we multiply 67/2 by 4/21.

= 67/2 * 4/21

To multiply fractions, multiply together the numerators, and multiply together the denominators. 67 * 4 = 268; 2 * 21 = 42

= 268/42

Using a calculator, 268/42 = 6.38095...

You can fill 6 full glasses.

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3 years ago

The points (6,y) and (7,9) fall on a line with a slope of 5 . What is the value of y ?

JulsSmile [24]

Answer:

y=4 (6,4)

Step-by-step explanation:

hope this helps!

7 0

3 years ago

Use the definition of the derivative to differentiate v=4/2 pie r^3

nata0808 [166]

I suspect 4/2 should actually be 4/3, since 4/2 = 2, while 4/3 would make V the volume of a sphere with radius r. But I'll stick with what's given:

$\displaystyle \frac{dV}{dr} = \lim_{h\to0} \frac{2\pi(r+h)^3-2\pi r^3}{h}$

$\displaystyle \frac{dV}{dr} = 2\pi \lim_{h\to0} \frac{(r^3+3r^2h+3rh^2+h^3)- r^3}{h}$

$\displaystyle \frac{dV}{dr} = 2\pi \lim_{h\to0} \frac{3r^2h+3rh^2+h^3}{h}$

$\displaystyle \frac{dV}{dr} = 2\pi \lim_{h\to0} (3r^2+3rh+h^2)$

$\displaystyle \frac{dV}{dr} = 2\pi \cdot 3r^2 = \boxed{6\pi r^2}$

In Mathematica, you can check this result via

D[4/2*Pi*r^3, r]

3 0

2 years ago

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Vlada [557]

Answer:

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2 years ago

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netineya [11]

Answer:

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3 years ago