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2 years ago

Two lengths are in the ratio 2:5. The second length is 75 cm. Find the first length.

Mathematics

1 answer:

vichka [17]2 years ago

7 0

Answer:

30 cm

Step-by-step explanation:

2 * 15: 5 * 15

30:75

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2 years ago

Consider the equation below.

Korvikt [17]

Answer:

Equation in square form:

$y=3(x+5)^2-4$

Extreme value:

$(h,k)=(-5,-4)$

Step-by-step explanation:

We are given

$y=3x^2+30x+71$

we can complete square

$y=3(x^2+10x)+71$

we can use formula

$a^2+2ab+b^2=(a+b)^2$

$y=3(x^2+2\times x\times 5)+71$

now, we can add and subtract 5^2

$y=3(x^2+2\times x\times 5+5^2-5^2)+71$

$y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71$

$y=3(x+5)^2-75+71$

So, we get equation as

$y=3(x+5)^2-4$

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

$y=a(x-h)^2+k$

where

vertex=(h,k)

now, we can compare and find h and k

$y=3(x+5)^2-4$

we get

h=-5

k=-4

so, extreme value of this equation is

$(h,k)=(-5,-4)$

6 0

3 years ago

Read 2 more answers

Please just give me the answer

Ber [7]

9514 1404 393

Answer:

Step-by-step explanation:

The Pythagorean theorem tells you of the relation ...

x² + 6² = 10² . . . . . . . . . squares of sides total to the square of hypotenuse

x² = 100 -36 = 64 . . . . . subtract 6²

x = √64 = 8 . . . . . . . . . . square root

The length of side x is 8 units.

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James wants to build a frame around a circular clock like the one shown. He is trying to determine how much material he needs to

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Answer:

Step-by-step explanation:

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2 years ago

Two lengths are in the ratio 2:5. The second length is 75 cm. Find the first length.​

Two lengths are in the ratio 2:5. The second length is 75 cm. Find the first length.