Answer: D.
Step-by-step explanation:
In the given figure, we have an obtuse triangle which has sides a, b, and c, and the angle opposite the side of length b is obtuse.
∵ In a triangle, the side opposite to the largest angle is largest.
Thus, the largest side in then given obtuse triangle= c
The Pythagorean inequalities theorem says that If a triangle is obtuse than the square of the largest side is greater than the sum of square of other two sides.
Therefore, we have
Using linear function concepts, it is found that:
- a) It costs $0.1 for each kilowatt hour of electricity used in excess of 250 kWh.
- b) f(90) = 46.6, which is the cost of 340 kWh of consumption in a month.
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A <em>linear function </em>has the format given by:
In which:
- m is the slope, which is the rate of change, that is, how much y changes when x changes by 1.
- b is the y-intercept, which is the value of y when x = 0.
The equation for the cost of h kilowatt hours (kWh) of electricity used in excess of 250 kWh is of:
Item a:
- The slope is of
, which means that it costs $0.1 for each kilowatt hour of electricity used in excess of 250 kWh.
Item b:
250 + 90 = 340.
f(90) = 46.6, which is the cost of 340 kWh of consumption in a month.
A similar problem is given at brainly.com/question/24808124
<h2>GOOD LUCK CHUCK :)))))))))</h2>
Discriminant = b^2 - 4ac, where a, b and c come from the form of the quadratic equation as ax^2 + bx + c
Discriminant = (4)^2 - 4(1)(5)
= 16 - 20
= -4
-4 < 0, therefor there are no roots
(If the discriminant = 0, then there is one root
If the discriminant > 0, there are two roots, and if it is a perfect square (eg. 4, 9, 16, etc.) then there are two rational roots
If the discriminant < 0, there are no roots)
Surface area of box=1200 cm²
<span>Volume of box=s²h </span>
<span>s = side of square base </span>
<span>h = height of box </span>
<span>S.A. = s² + 4sh </span>
<span>S.A. = surface area or 1200 cm², s²
= the square base, and 4sh = the four 'walls' of the box. </span>
<span>1200 = s² + 4sh </span>
<span>1200 - s² = 4sh </span>
<span>(1200 - s²)/(4s) = h </span>
<span>v(s) = s²((1200 - s²)/(4s)) </span>
<span>v(s) = s(1200 - s²)/4 . </span>
<span>v(s) = 300s - (1/4)s^3</span>
by derivating
<span>v'(s) = 300 - (3/4)s² </span>
<span>0 = 300 - (3/4)s² </span>
<span>-300 = (-3/4)s² </span>
<span>400 = s² </span>
<span>s = -20 and 20. </span>
again derivating
<span>v"(s) = -(3/2)s </span>
<span>v"(-20) = -(3/2)(-20) </span>
<span>v"(-20) = 30 </span>
<span>v"(20) = -(3/2)(20) </span>
<span>v"(20) = -30 </span>
<span>v(s) = 300s - (1/4)s^3 </span>
<span>v(s) = 300(20) - (1/4)(20)^3 </span>
<span>v(s) = 6000 - (1/4)(8000) </span>
<span>v = 6000 - 2000
v=4000</span>
