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Artemon [7]
3 years ago
9

Solve the system of equations by substitution. x + y = A system of equations. StartFraction 3 over 8 EndFraction x plus StartFra

ction one-third EndFraction y equals StartFractions 17 over 24 EndFraction. x + 7y = 8 ( , )
Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
8 0

Answer:

x=1 and y=1

Step-by-step explanation:

We have to solve by substitution the given system of equations:

\left \{ {{\frac{3}{8}x+\frac{1}{3}y=\frac{17}{24} }\atop {x+7y=8}} \right.

First, we have to choose an equation, no matter which one, and isolate a certain variable, no matter which one either. So, by our own criteria, we choose the second equation, and we'll isolate <em>x</em>:

x+7y=8\\x=8-7y

Now, this equivalence for x, we will replace it in the other equation, instead of <em>x</em>, we will put the result:

\frac{3}{8}(8-7y)+\frac{1}{3}y=\frac{17}{24}

Then, we solve for <em>y</em>:

\frac{3}{8}(8-7y)+\frac{1}{3}y=\frac{17}{24}\\\frac{3}{8}8-\frac{3}{8}7y+\frac{1}{3}y=\frac{17}{24}\\-\frac{21}{8}y+\frac{1}{3}y=\frac{17}{24}-3\\\frac{-63y+8y}{24}=\frac{17-72}{24}\\ \frac{-55y}{24}=\frac{-55}{24}\\y=\frac{-55(24)}{24(-55)}=1

Now, the final process will be to replace this y<em>-value </em>in one equation, no matter which one, and find x<em>-value</em>:

x+7y=8\\\\x+7(1)=8\\x=8-7\\x=1

Therefore, the solution of the system is x=1 and y=1

Akimi4 [234]3 years ago
7 0

Answer:

<h2>(1,1)</h2>

Step-by-step explanation:

juss took it

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