Answer:
A sample of 997 is needed.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of
.
The margin of error is of:

A previous study indicates that the proportion of left-handed golfers is 8%.
This means that 
98% confidence level
So
, z is the value of Z that has a p-value of
, so
.
How large a sample is needed in order to be 98% confident that the sample proportion will not differ from the true proportion by more than 2%?
This is n for which M = 0.02. So






Rounding up:
A sample of 997 is needed.
Dividing $72,000 by 4, each child received $18,000
The mean= 5.5
The median= 6
The range= 10
The IQR= 5
I really hope this helps:)
First, you need to move 2 to the other side. You accomplish this by adding 2 to 1. You have y>3. Since your variable is smaller than 3, draw an open circle on the 3 mark and a squiggly line left of 3.