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3 years ago

Estimate the product 0.62 x 104

Mathematics

1 answer:

oee [108]3 years ago

7 0

Answer:

The estimated product is 52.

Step-by-step explanation:

0.62 is 0.38 away from one and 0.12 away from 0.5. Since it's closer to 0.5, we'll round it to that. 104 doesn't need to be rounded because it's a whole number. So, 1/2 of 104 is 52. The estimated product is 52

Hope this helps! :)

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3 years ago

Which number is rational -3 1/2, sqrt 5, pi, 9.23157...

PIT_PIT [208]

-3 1/2 is rational because the decimal ends at -3.5. It is not sqrt(5) because the decimal never ends and the same follows for pi and 9.23157.

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3 years ago

Read 2 more answers

Which of the following is the expansion of (3c + d2)6?

vovangra [49]

Answer: Option A) $729c^6 + 1,458c^5d^2 + 1,215c^4d^4 + 540c^3d^6 + 135c^2d^8 + 18cd^{10} + d^{12}$ is the correct expansion.

Explanation:

on applying binomial theorem, $(a+b)^n=\sum_{r=0}^{n} \frac{n!}{r!(n-r)!} a^{n-r} b^r$

Here a=3c, $b=d^2$ and n=6,

Thus, $(3c+d^2)^6=\sum_{r=0}^{6} \frac{6!}{r!(6-r)!} (3c)^{n-r} (d^2)^r$

⇒ $(3c+d^2)^6= \frac{6!}{(6-0)!0!} (3c)^{6-0}.(d^2)^0+\frac{6!}{(6-1)!1!} (3c)^{6-1}.(d^2)^1+\frac{6!}{(6-2)!2!} (3c)^{6-2}.(d^2)^2+\frac{6!}{(6-3)!3!} (3c)^{6-3}.(d^2)^3+\frac{6!}{(6-4)!4!} (3c)^{6-4}.(d^2)^4+\frac{6!}{(6-5)!5!} (3c)^{6-5}.(d^2)^5+\frac{6!}{(6-6)!6!} (3c)^{6-6}.(d^2)^6$

⇒ $(3c+d^2)^6= \frac{6!}{(6-)!0!} (3c)^6.d^0+\frac{6!}{(5)!1!} (3c)^5.d^2+\frac{6!}{(4)!2!} (3c)^4.d^4+\frac{6!}{(6-3)!3!} (3c)^3.d^6+\frac{6!}{(2)!4!} (3c)^2.d^8+\frac{6!}{(1)!5!} (3c).d^{10}+\frac{6!}{(0)!6!} (3c)^0.d^{12}$

⇒ $(3c+d^2)^6=(3c)^6.d^0+\frac{720}{120} (3c)^5.d^2+\frac{720}{48} (3c)^4.d^4+\frac{720}{36} (3c)^3.d^6+\frac{720}{48} (3c)^2.d^8+\frac{720}{120} (3c).d^{10}+.d^{12}$

⇒ $(3c+d^2)^6=729c^6 + 1,458c^5d^2 + 1,215c^4d^4 + 540c^3d^6 + 135c^2d^8 + 18cd^{10} + d^{12}$

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3 years ago

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What is -1/2 + p = 5/8 simplified.

ra1l [238]

Add 1/2 to both sides:

$-\dfrac{1}{2}+p+\dfrac{1}{2} = \dfrac{5}{8}+\dfrac{1}{2} \iff p = \dfrac{5}{8}+\dfrac{1}{2} = \dfrac{5}{8}+\dfrac{4}{8} = \dfrac{9}{8}$

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Tomtit [17]

Answer:

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