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mamaluj [8]
2 years ago
6

Aria invested $96,000 in an account paying an interest rate of 1.8% compounded

Mathematics
1 answer:
Maslowich2 years ago
8 0

Answer:

9.2

Step-by-step explanation:

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A container is filled with 100 grams of bird feed that is 80% seed. Tom and Sally want to mix the 100 grams with bird feed that
zzz [600]

Answer:

Step-by-step explanation:

I need help to

5 0
2 years ago
Can u simplify 8/50 to a simpler fraction?
Licemer1 [7]
Yes u can because u can simplify it into 4/25 because they both have a factor of 2 which means they can both be divided by 2
7 0
2 years ago
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The CEO of the Jen and Benny's ice cream company is concerned about the net weight of ice cream in their 50 ounce ice cream tubs
MissTica

Answer:

t=\frac{54.98-52}{\frac{8.43}{\sqrt{26}}}=1.8025  

We need to find the degrees of freedom given by:

df = n-1= 26-1 = 25

Since is a right tailed test the p value would be:  

p_v =P(t_{25}>1.8025)=0.0418  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the average is higher than 52 at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=54.98 represent the sample mean

s=8.43 represent the sample deviation

n=26 sample size  

\mu_o =52 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 52, the system of hypothesis would be:  

Null hypothesis:\mu \leq 52  

Alternative hypothesis:\mu > 52  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{54.98-52}{\frac{8.43}{\sqrt{26}}}=1.8025  

P-value  

We need to find the degrees of freedom given by:

df = n-1= 26-1 = 25

Since is a right tailed test the p value would be:  

p_v =P(t_{25}>1.8025)=0.0418  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the average is higher than 52 at 5% of signficance.  

7 0
3 years ago
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The greatest comen factor of 21, 30,49
liq [111]
The greatest common factor for 21 is 7
For 30 is 15
49 is 7

I’m no totally sure but i think that is right
4 0
2 years ago
ANSWER ASAP PLS
katrin [286]

Answer:

21/6 can be divided by 3, so 7/2

7/2 cannot be divided into any more shared factors, so final answer is 7:2.

4 0
2 years ago
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