Factor the polynomial by substitution. 5(4n - 1)^2 + 23(4n – 1) -10

1 answer:

4 0

5(4n-1)^2 +23(4n-1)-10

5(4n-1)^2 +25(4n-1)- 2(4n-1)-10

5(4n-1)(4n-1+5)- 2(4n-1+5)

(4n-1+5) (5(4n-1)-2)

(4n+4) (20n-5-2)

4(n+1) (20n-7)

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Georgia [21]

Answer: A

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hram777 [196]

Answer:

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natima [27]

F(4) is 10 all you do is plug in 4 for x

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