A culture of 2.4 × 10^11 bacteria is in a Petri dish A
A culture of 8 × 10^9 bacteria is in Petri dish B
Number of times number of bacteria in Petri dish A is greater than that number in Petri dish B:

Divide 2.4 by 8 to give 0.3
Divide 10^11 by 10^9 to give 10^(11-9) = 10^2
The answer is 0.3 × 10²
40℅ of 152.5 = 61
250% of 61 = 152.5
Answer:
Step-by-step explanation:
15- 17 = a
-2 = a
B = -8.3
c = 3/4 - 13/4
c = -10/4
c = -5/2
2^2 x 3^2 is the answer to the question
921÷ 2 = 460.5
which means the remainder is 1
So; the answer is 1