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Tpy6a [65]
3 years ago
9

Last month a car dealership sold 80 cats. Of all cars sold 15% of them were red how many cars that were sold were red

Mathematics
2 answers:
telo118 [61]3 years ago
5 0

Answer:

12

Step-by-step explanation:

Multiply 80 by .15

serious [3.7K]3 years ago
4 0

it is 12............ :))

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What is the y-intercept of the graph of the function f(x) = x^2 + 3x + 5?
Semenov [28]

Answer:

(0,5)

Step-by-step explanation:

To find the y-intercept, substitute in 0 for x and solve for y.

y=x^2 + 3x + 5

y=(0)^2 + 3(0) +5

y=0+0+5

y=5

Since there is no x coordinate for a y-intercept, the answer is (0,5)

7 0
3 years ago
Write a polynomial function of least degree with integral coefficients that has the
frutty [35]

A polynomial function of least degree with integral coefficients that has the

given zeros  f(x)=x^4+x^3+9x^2+9x

Given

Given zeros are 3i, -1  and 0

complex zeros occurs in pairs. 3i is one of the zero

-3i is the other zero

So zeros are 3i, -3i, 0 and -1

Now we write the zeros in factor form

If 'a' is a zero then (x-a) is a factor

the factor form of given zeros

\:\left(x-3i\right)\left(x-\left(-3i\right)\right)\left(x-0\right)\left(x-\left(-1\right)\right)\\\left(x-3i\right)\left(x+3i\right)\left(x-0\right)\left(x+1\right)

Now we multiply it to get the polynomial

x\left(x-3i\right)\left(x+3i\right)\left(x+1\right)\\x\left(x^2+9\right)\left(x+1\right)\\x\left(x^3+x^2+9x+9\right)\\x^4+x^3+9x^2+9x

polynomial function of least degree with integral coefficients that has the

given zeros  f(x)=x^4+x^3+9x^2+9x

Learn more : brainly.com/question/7619478

6 0
3 years ago
What is the answer to y=-0.5(0)+2
Korolek [52]
The answer is: Y= 2.
3 0
3 years ago
Read 2 more answers
A one-parameter family of solutions of the de p' = p(1 − p) is given below.
tensa zangetsu [6.8K]

Answer:

A solution curve pass through the point (0,4) when c_{1} = -\frac{4}{3}.

There is not a solution curve passing through the point(0,1).

Step-by-step explanation:

We have the following solution:

P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}

Does any solution curve pass through the point (0, 4)?

We have to see if P = 4 when t = 0.

P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}

4 = \frac{c_{1}}{1 + c_{1}}

4 + 4c_{1} = c_{1}

c_{1} = -\frac{4}{3}

A solution curve pass through the point (0,4) when c_{1} = -\frac{4}{3}.

Through the point (0, 1)?

Same thing as above

P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}

1 = \frac{c_{1}}{1 + c_{1}}

1 + c_{1} = c_{1}

0c_{1} = 1

No solution.

So there is not a solution curve passing through the point(0,1).

3 0
3 years ago
Write the expression using a single exponent. (-3)^9 (-3)^4
Jet001 [13]

Answer:

(-3)^13

Step-by-step explanation:

(-3) is a constant value so there is no change

You must add 4 and 9 together to create one exponent of 13

6 0
3 years ago
Read 2 more answers
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