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Alexeev081 [22]
3 years ago
15

Equation A

Mathematics
1 answer:
NemiM [27]3 years ago
8 0

its c

Step-by-step explanation:

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The owner of a music store received a shipment of 1,532 CDs. The CDS came in 37 boxes. The same number of CDS were in 36 of the
aleksandr82 [10.1K]
1532 ÷ 36 = 42 and remain 20.
So there were 20 CDS in the remains box
8 0
3 years ago
An assembly line has two inspectors. The probability that the first inspector will miss a defective item is 0.06. If the defecti
Novay_Z [31]

Answer:

probability that both passes a defective item is  0.8742‬

<h3>Step-by-step explanation:</h3>

probability that the first inspector misses is Pr( 1st misses)= 0.06

therefore the probability he does not miss is

Pr(1st passes)= 1 - Pr( 1st misses) = 1 - 0.06 = 0.94

probability that the second misses is Pr( 2nd misses) = 0.07

therefore probability that 2nd does not miss is

Pr( 2nd passes) = 1- Pr( 2nd misses) = 0.93

probability that both passes a defective item is  Pr(1st passes)*Pr( 2nd passes)

= 0.93*0.94 = 0.8742‬

7 0
3 years ago
What is the horizontal asymptote for y(t) for the differential equation dy dt equals the product of 2 times y and the quantity 1
marta [7]
First, we need to solve the differential equation.
\frac{d}{dt}\left(y\right)=2y\left(1-\frac{y}{8}\right)
This a separable ODE. We can rewrite it like this:
-\frac{4}{y^2-8y}{dy}=dt
Now we integrate both sides.
\int \:-\frac{4}{y^2-8y}dy=\int \:dt
We get:
\frac{1}{2}\ln \left|\frac{y-4}{4}+1\right|-\frac{1}{2}\ln \left|\frac{y-4}{4}-1\right|=t+c_1
When we solve for y we get our solution:
y=\frac{8e^{c_1+2t}}{e^{c_1+2t}-1}
To find out if we have any horizontal asymptotes we must find the limits as x goes to infinity and minus infinity. 
It is easy to see that when x goes to minus infinity our function goes to zero.
When x goes to plus infinity we have the following:
$$\lim_{x\to\infty} f(x)$$=y=\frac{8e^{c_1+\infty}}{e^{c_1+\infty}-1} = 8
When you are calculating limits like this you always look at the fastest growing function in denominator and numerator and then act like they are constants. 
So our asymptote is at y=8.

3 0
3 years ago
01. Se tienen los angulos consecutivos AOB, BOC y COD. se cumple m&amp; AOC=125° m <br>​
Citrus2011 [14]

La diferencia entre los ángulos <em>AOB</em> y <em>COD</em> del sistema de tres ángulos <em>consecutivos</em> es igual a 25°.

La medida del ángulo BOC pertenenciente al sistema de tres ángulos consecutivos es igual a 20°.

<h3>Cómo analizar tres ángulos consecutivos</h3>

Por la geometría Euclídea conocemos que un conjunto de ángulos cuando comparten entre cada par de ángulos vecinos comparten el mismo vértice y la misma semirrecta.

De acuerdo con el enunciado, tenemos las siguientes condiciones:

∠AOB + ∠BOC = 125°   (1)

∠BOC + ∠COD = 100°  (2)

Por (1) y (2) tenemos las siguiente identidad:

∠AOB - 25° = ∠COD

∠AOB - ∠COD = 25°

La diferencia entre los ángulos <em>AOB</em> y <em>COD</em> del sistema de tres ángulos <em>consecutivos</em> es igual a 25°. \blacksquare

En el segundo caso, tenemos el siguiente sistema:

∠AOB = ∠BOC + ∠COD     (3)

∠AOB + ∠BOC - ∠COD = 40°     (4)

Por (3) y (4) tenemos la siguiente identidad:

2 · ∠BOC = 40°

∠BOC = 20°

La medida del ángulo BOC pertenenciente al sistema de tres ángulos consecutivos es igual a 20°. \blacksquare

Para aprender más sobre ángulos, invitamos cordialmente a ver esta pregunta verificada: brainly.com/question/21209282

8 0
2 years ago
Please help me it’s urgent
bezimeni [28]

Answer:

the answer would be y=2x+4

Step-by-step explanation:

4 0
3 years ago
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