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Sauron [17]
4 years ago
13

How to find the area under the standard normal curve between z 1.5 and z 2.5?

Mathematics
1 answer:
alisha [4.7K]4 years ago
8 0
It is possible to calculate mathematically the area under the normal curve between any two values of z.
However, tables/software have been developed to give the areas under the normal curve to the left of particular values of z.  The function is the probability of Z<z, or P(Z<z).
The area between two values z1 and z2 (where z2>z1) is therefore 
P(Z<z2)-P(Z<z1).

For example, to find the area between  z1=1.5, z2=2.5
is 
P(Z<2.5)-P(Z<1.5)
=0.99379-0.93319
=0.06060

(above values obtained by software, such as R)
For example, the value P(Z<2.5) can be calculated using
P(Z<2.5)=erf(2.5/sqrt(2))/2+1/2
where erf(x) is a mathematical function that does not have an explicit formula (calculated by summation of series, or tabulated).
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Form quadratic functions given the following information:
nignag [31]

Answer:

f(x)=-\frac{4}{7}(x-\sqrt{2}-3)(x+\sqrt{2}-3)

or

f(x)=-\frac{4}{7}(x^2-6x+7)

Step-by-step explanation:

we have

f(3+√2 )=f(3− √2 )=0

so

x1=3+√2 and x2=3−√2 are the roots or x-intercepts of the quadratic equation

The quadratic equation in factored form is equal to

f(x)=a(x-x1)(x-x2)

substitute

f(x)=a(x-(3+\sqrt{2}))(x-(3-\sqrt{2}))

Find the value of the coefficient a

Remember that

f(1)=−8

so

For x=-1 -----> f(x)=-8

substitute

-8=a(-1-(3+\sqrt{2}))(-1-(3-\sqrt{2}))

solve for a

-8=a(-4-\sqrt{2}))(-4+\sqrt{2}))

apply difference of squares

-8=a(14)

a=-\frac{4}{7}

therefore

f(x)=-\frac{4}{7}(x-(3+\sqrt{2}))(x-(3-\sqrt{2}))

f(x)=-\frac{4}{7}(x-\sqrt{2}-3)(x+\sqrt{2}-3)

simplify

Applying distributive property

f(x)=-\frac{4}{7}(x^2+\sqrt{2}x-3x-\sqrt{2}x-2+3\sqrt{2}-3x-3\sqrt{2}+9)

f(x)=-\frac{4}{7}(x^2-6x+7)

5 0
4 years ago
PLEASE SOMEONE ANSWER THIS ASAP !!!!!!!!!
kotykmax [81]

Answer:

for the second one,

f(4)= 2⁴-7= 9

g(4)= 1.5x4-3= 3

therefore 9>3

f(4)>g(4)

8 0
3 years ago
Identify a transformation of the function f(x) = (x) by observing the equation of the function g(x) = (x)+56.
umka2103 [35]

Answer:

A: a vertical shift 56 units upward I believe

7 0
3 years ago
In a rectangle MPKN, the diagonals intersect each other at point O. A line segment OA is an altitude of a triangle MOP, and m∠AO
WINSTONCH [101]

Answer:

72

Step-by-step explanation:

6 0
3 years ago
The data for Shawn's phone has 32000 megabytes if storage for photos . She wants to increase the amount by 4% if each photo uses
Law Incorporation [45]

Answer:

Yes, she will have have enough new memory for 200 additional photos.

Step-by-step explanation:

Given:

Initial memory for storage, M_{o}=32000\textrm{ megabytes}

Increase in memory =4%

Therefore, increase in memory, \Delta M=\frac{4}{100}\times 32000=1280\textrm{ megabytes}

Now, memory consumed by 1 photo = 5 megabytes

So, memory consumed by 200 additional photos = 200\times 5=1000\textrm{ megabytes}

Memory left in her phone = 1280 - 1000 = 280 megabytes

Therefore, she will have additional 280 megabytes of memory left in her phone.

As memory consumed by 200 additional photos is less than that of the increase in memory, therefore, she does have enough new memory for 200 additional photos.

6 0
3 years ago
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