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azamat
3 years ago
10

What is the surface of a area of the square 10m 10m 8m

Mathematics
1 answer:
MatroZZZ [7]3 years ago
5 0

Answer: The area is  (800)

Step-by-step explanation: (10x 10= 100)

(100 x 8= 800)

FINAL ANSWER: 800m

~ i really hope this is correct, have a gr8 day/night my friend!~

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romanna [79]

Answer:

The answer is c definitely

6 0
3 years ago
Read 2 more answers
Find the domain y = 7 - 4x / |2x + 5| + 3
murzikaleks [220]

Answer:

Find the domain by finding where the equation is defined. The range is the set of values that correspond with the domain.

Domain: (−∞,∞),{x|x∈R}Range: (−∞,∞),{y|y∈R}

Step-by-step explanation:

4 0
3 years ago
An equilateral triangle has a perimeter of 15x + 33x feet. What is the length of each side?
Zinaida [17]

Answer:

is there any mistake in your question?

Step-by-step explanation:

(15x + 33x) / 3 = 5x + 11x = 16x

8 0
3 years ago
Point b lies on the segment ac . Find the length of the segment ac, if ab=7.8 cm, bc=25mm. How many different solutions can this
ladessa [460]

The length of the segment ac is 10.3 cm

<h3>How to determine the length ac?</h3>

The segments are given s:

ab = 7.8cm

bc = 25mm

Point b is located between points a and c.

So, we have:

ac = ab + bc

Substitute known values

ac = 7.8cm + 25mm

Express mm a  cm

ac = 7.8cm + 2.5cm

Evaluate the sum

ac = 10.3 cm

If the point b lies on segment ac, then there can be only one solution

Read more about line segment at:

brainly.com/question/2437195

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7 0
2 years ago
he U.S. Bureau of Labor Statistics reports that the average annual expenditure on food and drink for all families is $5700. Assu
Papessa [141]

Answer:

87.08% percentage of families spend more than $4000 annually on food and drink

Step-by-step explanation:

Given -

average annual expenditure on food and drink for all families is $5700

Mean  (\nu) = 5700

standard deviation (\sigma ) = 1500

Let X be the no of families spend annually on food and drink

percentage of families spend more than $4000 annually on food and drink =

P(X > 4000)  = P(\frac{X - \nu }{\sigma }> \frac{ 4000 - 5700}{1500})

                      =  P(Z > - 1.13)     Using  (Z = \frac{X - \nu }{\sigma })

                      =  1 - P(Z

                      = 1 - .1292

                      = .8708

                       = 87.08%

7 0
4 years ago
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