In both the figures we have a Right Angled Triangle.
Two sides of the right angled triangles are given and we are to find the Third side. This can be done using the Pythagoras Theorem, which states:
Hypotenuse² = Base² + Perpendicular²
For 1st figure, we have
Base = 21
Perpendicular = 20
So,
Hypotenuse² = 20² + 21² = 841
⇒
Hypotenuse = 29 (1st option is correct)
For 2nd Image, we have
Base= 6
Hypotenuse = 10
So, we can write:
10² = 6² + Perpendicular²
Perpendicular² = 64
⇒
Perpendicular = 8 (Option Fourth)
Area = length * width
A = 60 * 20
A = 120 square feet
Answer: Oliver is correct
Step-by-step explanation:*mine doesn’t have the line and stuff to show u how to explain it*
Answer:
1) m∠U = 90°
2) m∠C = 80°
Step-by-step explanation:
1) The given figure is a quadrilateral
The sum of the interior angles of quadrilateral = 360°
∴ The sum of the interior angles of the given figure = 360°
Therefore, we have;
80° + 24·x + 4 + 6 + 21·x + 90° = 360°
80° + 45·x + 10 + 90° = 360°
x = (360°- (80° + 10° + 90°))/45 = 4
x = 4
m∠U = 6 + 21·x = 6 + 21 × 4 = 90
m∠U = 90°
2) The sum of the interior angles of the given quadrilateral = 360°
∴ 21·x + 6 + 20·x + 24·x + 4 + 21·x + 6 = 360°
86·x + 16 = 360°
x = (360° - 16°)/86 = 4
x = 4
m∠C = 20·x = 20 × 4 = 80
m∠C = 80°
3) In the figure, some angles are left out, therefore, more information on the remaining angles required
(6x -2) 2 (0.5) 4
(6x -2) 4
24x -8
Solution
24x -8
