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marin [14]
2 years ago
8

Help please n ty :P sdhgfahedgewkgfzndb

Mathematics
1 answer:
Ugo [173]2 years ago
3 0

Answer:

y=-3.2\\\\y=-2.2\\\\y=-1.8

Step-by-step explanation:

Insert the given x values for the given equation to find the corresponding y coordinate:

y=0.2x-2

x:-6,-1,1

Insert -6:

y=0.2(-6)-2

Simplify multiplication (when multiplying a negative and a positive, the result will always be negative):

y=-1.2-2

Simplify (when subtracting from a negative number, add the values, but keep the negative symbol):

y=-3.2

Insert -1:

y=0.2(-1)-2\\\\y=-0.2-2\\\\y=-2.2

Insert 1:

y=0.2(1)-2\\\\y=0.2-2\\\\y=-1.8

:Done

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Simple question just answer correctly to get brainleist and 10 pts! :)
Natali [406]

Answer:

d.  The mapping represents y as a function of x, because each x-value corresponds to exactly one y-value.

Step-by-step explanation:

This would be a function as long as one x-value doesn't correspond to two y-values. If two x-values correspond to one y-value though, it still represents a function.

8 0
2 years ago
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What’s 33345 times 234654?
Rudiy27

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Step-by-step explanation:

5 0
3 years ago
Gary is 8 years older than his brother. Six years ago Gary was three times as old as his brother. How old are they now?
Yuliya22 [10]

Answer:Gary-18 years brother-10 years

Step-by-step explanation:1st case: brother=1 yrs,gary=3 yrs=>after 6 after: brother =7 yrs gary=9 years

2nd case:......

3rd case:.....

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8 0
3 years ago
Someone help?!.........
koban [17]
Answer: y = -2x + 16

Explanation:

Use point slope form:

(y1 - y) = m(x1 - x)

y1 = 6 and x1 = 5 and m = -2

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5 0
2 years ago
find two consecutive odd integers whose product is 1 less than 6 times their sum. Domain for the smallest : {-1, 1, 11}
inn [45]
Let x be the 1st odd number, and x+2 the second odd consecutive number:

(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1

x² + 2x = 12x +12 - 1
And x² - 10x - 11=0

Solve this quadratic expression:

x' = [+10 +√(10²- 4.(1)(-11)]/2  and x" = [+10 -√(10²- 4.(1)(-11)]/2

x' = [10 + √144]/2      and  x" = [10 - √64]/2

x' = (10+12)/2    and x" = (10-12)/2

x = 11 and x = -1

We have 2 solutions that satisfy the problem:

1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity


6 0
3 years ago
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