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1. The major arc ED has measure 180 degrees since ED is a diameter of the circle. The measure of arc EF is
, so the measure of arc DF is

The inscribed angle theorem tells us that the central angle subtended by arc DF,
, has a measure of twice the measure of the inscribed angle DEF (which is the same angle OEF) so

so the measure of arc DF is also 64 degrees. So we have

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2. Arc FE and angle EOF have the same measure, 56 degrees. By the inscribed angle theorem,

Triangle DEF is isosceles because FD and ED have the same length, so angles EFD and DEF are congruent. Also, the sum of the interior angles of any triangle is 180 degrees. It follows that

Triangle OFE is also isosceles, so angles EFO and FEO are congruent. So we have

Now, the cosecant of θ is -6, or namely -6/1.
however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.
we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

recall that

therefore, let's just plug that on the remaining ones,

now, let's rationalize the denominator on tangent and secant,
Answer:
Step-by-step explanation:
Here you go mate
Step 1
(-5)(5) +5 Equation
Step 2
(-5)(5) +5 Simplify
(-5)(5) +5
Step 3
(-5)(5) +5 Add and multiply them
(-25)+5
answer
-20